Question

这while没有停止，似乎停留在无限循环中：

struct list_elem<int[5]> *p, *pCopy; // list_elem is  the node struct
p = l.pfirst;                        // l is the LL object

pCopy = p->next;

while(p != NULL) { 
   //bunch of code
   p = pCopy; 
}

将关闭问题

简单地pCopy是一个常数，因为它在循环之外。谢谢你的帮助

Answer 1

这就是你如何迭代：

while(p != NULL) { 
   p = p->next; 
}

.运算符用于本地结构，而->取消引用指针：

#include <stdio.h>
#include <string.h>

struct my_struct {

    int id;
    struct my_struct *next;    
}

int main()
{
    struct my_struct *a, *b, *c;

    a = malloc(sizeof(struct my_struct));
    b = malloc(sizeof(struct my_struct));
    c = malloc(sizeof(struct my_struct));

    a->next = b;
    a->id = 1;

    b->next = c;
    b->id = 2;

    c->next = NULL;
    c->id = 3;

    struct my_struct *it = a;

    printf("Using pointers:\n\n");

    while(it != NULL) {
        printf("Element %d\n", it->id);

        it = it->next;
    }

    struct my_struct d, e, f;

    d.next = &e;
    d.id = 1;

    e.next = &f;
    e.id = 2;

    f.next = NULL;
    f.id = 3;

    it = &d;

    printf("Using locals:\n\n");

    while(it != NULL) {
        printf("Element %d\n", it->id);

        it = (it->next);
    }

    free(a);
    free(b);
    free(c);

    return 0;
}

你应该谷歌上一篇关于C的教程，并且首先尝试理解指针算术。

Answer 2

while ((p = p->next) != NULL);

你所拥有的并不是真正通过列表，只是一遍又一遍地设置自己

指针和引用（C ++）

2 个答案: