Question

我需要帮助验证一个switch case语句我需要它来检查用户输入的内容以及它是否匹配拒绝它并告诉他们再次执行此操作。我现在所拥有的那个部分有效，但会拒绝第一个数字，然后在尝试输入另一个数字时中断。帮助如果您需要查看整个程序，请询问。

#include "stdafx.h"
#include "cstdlib"
#include "iostream"
#include "windows.h"
#include "cmath"


using namespace std;

int main(int argc, char* argv[])
{


float ALT0();
float ALT5000();
float ALT10000();
float ALT15000();
float ALT20000();
float ALT25000();
float ALT30000();
float ALT35000();
float ALT40000();
void an_answer(float a);

char Restart;
char op;
float answer;

do
{
cout << "\n\t\t\tOperational Flight Plan\n" << endl;

cout << "For the saftey of everyone on board, there will be 100 kg added to the overall\namount to give the aircraft more fuel incase of a head on wind or delays at the landing airport.\n" << endl;
cout << "Select Altitude the aircraft will fly at: " << endl;
cout << "0 for 0ft\n1 for 5000ft\n2 for 10000ft\n3 for 15000ft\n4 for 20000ft\n5 for 25000ft\n6 for 30000ft\n7 for 35000ft\n8 for 40000ft" << endl;
cin >> op;
switch (op)
{
case'0':
    answer=ALT0();
    break;

case '1':
    answer=ALT5000();
    break;

case '2':
    answer=ALT10000();
    break;

case '3':
    answer=ALT15000();
    break;

case '4':
    answer=ALT20000();
    break;

case '5':
    answer=ALT25000();
    break;

case '6':
    answer=ALT30000();
    break;

case '7':
    answer=ALT35000();
    break;

case '8':
    answer=ALT40000();
    break;
    default:
        cout << "You must enter a number from 0-8" << endl;
        cin >> op;

    break;

}

an_answer(answer);

cout << "Do you want to do another calculation? Press Y for yes and anything else to quit.";
cin >> Restart;
} while (Restart=='y' || Restart=='Y');

//system("PAUSE");
//return EXIT_SUCCESS;
}

Answer 1

我打赌你在输入号码后打击输入。您的第一个cin >> op读取该号码，但您的第二个读取回车键。如果要读取整行，请使用读取整行的函数。

或者，将第二个cin >> op移至switch语句之前。如果有人在点击输入之前输入了多个字符，这将会中断，否则将会起作用。

在switch case语句中循环

1 个答案: