Question

我试图操作的代码是绘制方法...我试图通过均匀填充方块来显示棋盘，但是当我运行程序并将滑块移动到均匀时它给了我一个列，黑色的一个列，空的等等。在奇数时它是国际象棋棋盘

import java.awt.*;
import javax.swing.*;
import java.awt.event.*;
import javax.swing.event.*;

public class Blobs extends JFrame implements ActionListener, ChangeListener {

private MyCanvas canvas = new MyCanvas();
private JSlider sizeSl = new JSlider(0, 20, 0);
private JButton reset = new JButton("RESET");
private int size = 0; // number of lines to draw

public static void main(String[] args) {
    new Blobs();
}
public Blobs() {
    setLayout(new BorderLayout());
    setSize(254, 352);
    setTitle("Blobs (nested for)");
    sizeSl.setMajorTickSpacing(5);
    sizeSl.setMinorTickSpacing(1);
    sizeSl.setPaintTicks(true);
    sizeSl.setPaintLabels(true);
    add("North", sizeSl);
    sizeSl.addChangeListener(this);
    add("Center", canvas);
    JPanel bottom = new JPanel();
    bottom.add(reset);
    reset.addActionListener(this);
    add("South", bottom);
    setResizable(false);
    setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    setVisible(true);
}

public void actionPerformed(ActionEvent e) {
    size = 0;
    sizeSl.setValue(0);
    canvas.repaint();
}

public void stateChanged(ChangeEvent e) {
    size = sizeSl.getValue();
    canvas.repaint();
}

private class MyCanvas extends Canvas {

    @Override
    public void paint(Graphics g) {
        int x, y;
        int n = 0;
        for (int i = 0; i < size; i++) {
            //n = 1 + i;
            for (int j = 0; j < size; j++) {
                n++;
                x = 20 + 10 * i;
                y = 20 + 10 * j;
                //g.fillOval(x, y, 10, 10);
                g.drawRect(x, y, 10, 10);

                if (n % 2 == 0) {
                g.fillRect(x, y, 10, 10);
                }
                }
            }
        }
    }
}

Answer 1

如果按顺序排列NxN国际象棋棋盘的方格，其中N为偶数，则每N个方格你会连续得到两个相等的棋盘。

因此，如果尺寸均匀，则必须相应地调整方法：

for (int i = 0; i < size; i++) {
    n += size % 2 + 1;
    for (int j = 0; j < size; j++) {
        n++;
        //...

Answer 2

问题是你用n计算绘制的矩形的数量。这不适用于奇数。轻松修复：

for (int i = 0; i < size; i++) {
  n = (i % 2);

这会将每行的计数器n交替重置为0和1。

棋盘游戏java

2 个答案: