Question

enter image description here

我的查询数据设计如下表所示：

SHIPMENT_NO     SHIPMENT_DATE   PART_NAME   BOX_NUMBER
DG3-14040001    4/24/2014       TEST        S201551254
DG3-14040001    4/24/2014       TEST        S010101010
DG3-14040001    4/24/2014       TEST        S100200123
DG2-14040001    4/24/2014       DG-M11-A    S001545525

我想要的是：

SHIPMENT_NO     SHIPMENT_DATE   PART_NAME   BOX_NUMBER
DG3-14040001    4/24/2014       TEST        S201551254
                4/24/2014       TEST        S010101010
                4/24/2014       TEST        S100200123
DG2-14040001    4/24/2014       DG-M11-A    S001545525

因为发货没有DG3-14040001相同，所以它只会显示1个值。

这是My Oracle SQL：

SELECT SHIPMENT_NO, SHIPMENT_DATE, PART_NAME, BOX_NUMBER FROM DIGI_SHIPMENT_SCAN WHERE TO_CHAR(SHIPMENT_DATE,'YYYY-MM-DD') BETWEEN '$start_date' AND '$end_date' GROUP BY SHIPMENT_NO, SHIPMENT_DATE, PART_NAME, BOX_NUMBER

while($d1 = oci_fetch_array($result_q1))
{
$shp_no = $d1['SHIPMENT_NO'];
$shp_date = $d1['SHIPMENT_DATE'];
$part_name = $d1['PART_NAME'];
$box_number = $d1['BOX_NUMBER'];

SELECT COUNT(*) AS TOTAL_SHP FROM DIGI_SHIPMENT_SCAN WHERE TO_CHAR(SHIPMENT_DATE,'YYYY-MM-DD') BETWEEN '$start_date' AND '$end_date' AND SHIPMENT_NO = '$shp_no'
$result_q3 = oci_parse($c1, $q3);
oci_execute($result_q3);

$d3 = oci_fetch_array($result_q3);
$total_shp = $d3['TOTAL_SHP'];

<td class="td_brd7 td_brd6" rowspan="<?php echo $total_shp; ?>"><?php echo $shp_no; ?></td>
<td class="td_brd7 td_brd6" rowspan="<?php echo $total_shp; ?>"><?php echo $shp_date; ?></td>
<td class="td_brd7 td_brd6" rowspan="<?php echo $total_shp; ?>"><?php echo $part_name; ?></td>
<td class="td_brd7 td_brd6" rowspan="<?php echo $total_shp; ?>"><?php echo $box_number; ?></td>
}

当结果出现时，它将显示Double Shipment No取决于BOX Number总行查询。

您可以在图片上看到，出货号应该显示1值，因为相同的值。

请提供建议。

Answer 1

这通常应该在您的应用程序逻辑中完成，但也可以通过巧妙地使用LAG（）函数来完成。

LAG（）允许您根据特定顺序评估上一行。然后，当它与前一行相同时，可以应用CASE WHEN显示NULL。

http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions070.htm

示例：

SELECT CASE WHEN LAG(Shipment_No)
     OVER (ORDER BY Shipment_No, Order_Date)  = Shipment_NO
     THEN NULL ELSE Shipment_No END AS Shipment_NO,
    (...)
FROM YourTable
ORDER BY Shipment_No, Order_Date;

Answer 2

这种格式化确实应该在应用程序级别完成，即使在SQL中也是如此。从表的一行中删除值会使结果不再是关系数据集。

您可以使用LAG()：

执行此操作

SELECT (CASE WHEN SHIPMENT_NO = LAG(SHIPMENT_NO) OVER (ORDER BY SHIPMENT_NO, SHIPMENT_DATE, PART_NAME, BOX_NUMBER) AND
                  SHIPMENT_DATE = LAG(SHIPMENT_DATE) OVER (ORDER BY SHIPMENT_NO, SHIPMENT_DATE, PART_NAME, BOX_NUMBER) AND
                  PART_NAME = LAG(PART_NAME) OVER (ORDER BY SHIPMENT_NO, SHIPMENT_DATE, PART_NAME, BOX_NUMBER) 
             THEN ''
             ELSE SHIPMENT_NO
        END) as SHIPMENT_NO,
       DSS.SHIPMENT_DATE, DSS.PART_NAME, DSS.BOX_NUMBER
FROM DIGI_SHIPMENT_SCAN DSS
WHERE TO_CHAR(SHIPMENT_DATE,'YYYY-MM-DD') BETWEEN '$start_date' AND '$end_date'
GROUP BY DSS.SHIPMENT_NO, DSS.SHIPMENT_DATE, DSS.PART_NAME, DSS>BOX_NUMBER
ORDER BY DSS.SHIPMENT_NO, DSS.SHIPMENT_DATE, DSS.PART_NAME, DSS.BOX_NUMBER;

这样做需要处理一些细微之处。输出需要明确排序。除非包含order by子句，否则不能依赖结果集的顺序。然后，您需要对lag()使用相同的顺序，而不使用partition by子句。

请注意，查询还使用表别名。这是因为列别名SHIPMENT_NO可能与DSS.SHIPMENT_NO子句中的列order by混淆。您需要具体，或者所有空白列将一起显示。

Answer 3

如何使用break on？

break on SHIPMENT_NO;
SELECT SHIPMENT_NO, SHIPMENT_DATE, PART_NAME, BOX_NUMBER 
FROM DIGI_SHIPMENT_SCAN WHERE 
TO_CHAR(SHIPMENT_DATE,'YYYY-MM-DD')
BETWEEN '$start_date' AND '$end_date' GROUP BY
SHIPMENT_NO, SHIPMENT_DATE, PART_NAME, BOX_NUMBER

http://docs.oracle.com/cd/B19306_01/server.102/b14357/ch6.htm

禁止中断列中的重复值

BREAK命令默认在您命名的列或表达式中禁止重复值。因此，要抑制ORDER BY子句中指定的列中的重复值，请以最简单的形式使用BREAK命令：

BREAK ON break_column

注意：无论何时在BREAK命令中指定列或表达式，请使用指定相同列或表达式的ORDER BY子句。如果不这样做，每次列值更改时都会发生中断。示例6-10抑制中断列中的重复值

要在显示的查询结果中禁止显示重复的部门编号，请输入以下命令：

BREAK ON DEPARTMENT_ID;

对于以下查询（存储在缓冲区中的当前查询）：

SELECT DEPARTMENT_ID, LAST_NAME, SALARY
FROM EMP_DETAILS_VIEW
WHERE SALARY > 12000
ORDER BY DEPARTMENT_ID;
DEPARTMENT_ID LAST_NAME 



               SALARY
------------- ------------------------- ----------
           20 Hartstein                      13000
           80 Russell                        14000
              Partners                       13500
           90 King                           24000
              Kochhar                        17000
              De Haan                        17000

6 rows selected.

PHP Oracle查询数据分组

3 个答案: