我有一个上传页面,用户只能上传CSV文件。但是,当我点击上传按钮时,没有任何内容上传到我的数据库,也没有显示任何错误消息。只有返回按钮显示这意味着我的代码不能正确执行我的代码。我该如何解决这个问题?
CREATE TABLE `Jobs` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`date` date NOT NULL,
`order_ref` varchar(250) NOT NULL,
`first_name` varchar(250) NOT NULL,
`last_name` varchar(250) NOT NULL,
`postcode` varchar(250) NOT NULL,
`country` varchar(250) NOT NULL,
`quantity` varchar(250) NOT NULL,
`scott_packing` varchar(250) NOT NULL,
`packing_price` varchar(250) NOT NULL,
`courier_price` varchar(250) NOT NULL,
`dispatch_type` varchar(250) NOT NULL DEFAULT '',
`tracking_number` varchar(250) NOT NULL,
`job_status` varchar(250) NOT NULL,
`created` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
PRIMARY KEY (`id`)
)
HTML:
<?
session_start();
if(!session_is_registered(myusername))
{
header("location:../index.php");
}
?>
<?
include("../template/header.php");
?>
<!DOCTYPE html>
<head>
<title></title>
<meta http-equiv="content-type" content="text/html; charset=UTF-8">
</head>
<body>
<div class="content">
<div class="toggle">
<div class="header"><img style="float: right; padding: 10px;" src="../img/show.gif"><h4>Upload New File:</h4></div>
<form id="upload" action="upload_file.php" method="post" enctype="multipart/form-data">
<input type="file" name="uploaded_file"><br>
<input type="submit" value="Upload file">
</form>
<!--<p>
<a href="list_files.php" style="padding: 20px;">See all files</a>
</p>-->
</div>
</div>
</body>
</html>
upload_file.php:
<?php
if(isset($_FILES['uploaded_file'])) {
if($_FILES['uploaded_file']['error'] == 0) {
$database = "spineless";
$dblink = mysql_connect("localhost", "root", "vario007")
or die("Could not connect");
$db = mysql_select_db($database)
or die("Could not select database");
if(mysql_errno()) {
die("MySQL connection failed: ". mysql_error());
}
$file = $_FILES ['uploaded_file']['tmp_name'];
$handle = fopen($file, "r");
$row = 1;
while (($data = fgetcsv($handle, 0, ",","'")) !== FALSE)
{
if($row == 1)
{
// skip the first row
}
else
{
//csv format data like this
//$row[0] = date
//$row[1] = order_ref
//$row[2] = postcode
//$row[3] = country
//$row[4] = quantity
//$row[5] = packing_price
//$row[6] = dispatch_type
$query = "
INSERT INTO `Jobs` (
`date`, `order_ref`, `postcode`, `country`, `quantity`, `packing_price`, `dispatch_type`, `created`
)
VALUES (
'".$data[0]."', '".$data[1]."', '".$data[2]."', '".$data[3]."', '".$data[4]."', '".$data[5]."', '".$data[6]."', NOW()
)";
$result = mysql_query($query);
// Check if it was successfull
if(!$result) {
echo 'Success! Your file was successfully added!';
}
else {
echo 'Error! Failed to insert the file';
}
}
$row++;
}
}
else {
echo 'An error accured while the file was being uploaded. '
. 'Error code: '. intval($_FILES['uploaded_file']['error']);
}
// Close the mysql connection
mysql_close();
}
else {
echo 'Error! A file was not sent!';
}
// Echo a link back to the main page
echo '<p>Click <a href="joblist.php">here</a> to go back</p>';
?>
这就是CSV的样子: http://i754.photobucket.com/albums/xx182/rache_R/Screenshot2014-04-24at151348_zps807cedb0.png
答案 0 :(得分:1)
所以我设法解决了自己的问题。在查看我的代码之后,我注意到我的代码在while循环之前已经很好了。在读取文件时,PHP无法正确识别行结尾,因此启用auto_detect_line_endings
运行时配置有助于解决我的问题。请注意,auto_detect_line_endings
应设置在 fopen
之前,而不是之后。
<?php
if(isset($_FILES['uploaded_file'])) {
if($_FILES['uploaded_file']['error'] == 0) {
// Connect to database
$database = "spineless";
$link = mysql_connect("localhost", "root", "vario007") or die("Could not connect");
$db = mysql_select_db($database,$link) or die("Could not select database");
// Upload file
$file = $_FILES['uploaded_file']['tmp_name'];
ini_set("auto_detect_line_endings", true); // auto_detect_line_endings added here
$handle = fopen($file, "r");
$row = 1;
while (($data = fgetcsv($handle, 0, ",","'")) !== FALSE)
{
if($row == 1)
{
// skip the first row
}
else
{
//csv format data like this
//$row[0] = date
//$row[1] = order_ref
//$row[2] = postcode
//$row[3] = country
//$row[4] = quantity
//$row[5] = packing_price
//$row[6] = dispatch_type
$query = "
INSERT INTO `Jobs` (
`date`, `order_ref`, `postcode`, `country`, `quantity`, `packing_price`, `dispatch_type`, `created`
)
VALUES (
'".$data[1]."', '".$data[2]."', '".$data[5]."', '".$data[6]."', '".$data[7]."', '".$data[9]."', '".$data[11]."', NOW()
)";
$result = mysql_query($query);
// Check if it was successfull
if($result) {
echo 'Success! Your file was successfully added!';
}
else {
echo 'Error! Failed to insert the file';
}
}
$row++;
}
}
else {
echo 'An error accured while the file was being uploaded. ';
}
// Close the mysql connection
mysql_close();
}
else {
echo 'Error! A file was not sent!';
}
// Echo a link back to the main page
echo '<p>Click <a href="joblist.php">here</a> to go back</p>';
?>
答案 1 :(得分:0)
好的,我根据您的信息设置了一个数据库,并使用您提供的数据创建了一个CSV文件。好消息是你的代码对我来说非常好(对我而言),但对于两个小问题。
您的成功消息是错误的,请删除!
:
if($result){
echo 'Success! Your file was successfully added!';
}else{
echo 'Error! Failed to insert the file';
}
您还尝试将日期字符串03/02/2014
插入DATE数据类型。这不会起作用,您需要相应地格式化此字符串。作为临时措施,我只是将DB中的数据类型更改为VARCHAR(20)。
修复了这两件小事:
答案 2 :(得分:0)
<?
session_start();
在输出发送到浏览器之后,您无法启动会话,在这种情况下,会有一些空白空间。
调整此项,最好不要使用任何类型的short_open_tags
:
<?php
session_start();