Question

我正在尝试使用Django上传csv文件并计划解析CSV文件。但是这段代码无法上传文件并继续进入else条件。这段代码有什么问题？谢谢！

Old Class            New Class
ASN1Object           ASN1Primitive
ASN1Encodable        ASN1Object
DEREncodable         ASN1Encodable
DERObject            ASN1Primitive
DERString            ASN1String
DERObjectIdentifier  ASN1ObjectIdentifier
X509Name             X500Name
DERInteger           ASN1Integer
DEREnumerated        ASN1Enumerated
X509Attributes       X509AttributeIdentifiers
X509Extension        Extension

template.html

from django.shortcuts import render
from django.shortcuts import render_to_response
from django.template import RequestContext
from django.http import HttpResponseRedirect
from django.core.urlresolvers import reverse

import csv
import codecs

from items.models import UploadFileForm


def handle_files(f):
    reader = csv.DictReader(open(f))
    for row in reader:
    print row

def home(request):
    if request.method == "POST":
        form = UploadFileForm(request.POST, request.FILES)
        if form.is_valid():
            handle_files(request.FILES['file'])
            return HttpResponseRedirect('/workflow/')
        else:
            print form.errors
            print request.FILES
            return HttpResponseRedirect('/workflow/upload')

    else:
        form = UploadFileForm()
        return render(request, 'template.html', {'formset': form})

forms.py

<form action="" method="post" enctype="multipart/form-data">{% csrf_token %}

   <input type="file" name="csv_file" />
   <input type="submit" value="Upload" />

</form>

Answer 1

相反，您可以尝试（除非您启用了验证，否则无需检查表单是否有效）：

def home(request):
    if request.method == "POST":
        if request.FILES:
            handle_files(request.FILES['file'])
            return HttpResponseRedirect('/workflow/')
        else:
            return HttpResponseRedirect('/workflow/upload')

    else:
        form = UploadFileForm()
        return render(request, 'template.html', {'formset': form})

无法使用Python / Django上传CSV文件

1 个答案: