Question

我担心这很可能只是一个老式的错过角色，但我很难过。还有其他人为括号打猎吗？ :)我使用以下函数在标题中得到编译器错误。救命？提前谢谢！

int print(char* cmd2, int sockfd)
{
    int cmdNum;
    int n;
    int numR;
    int i;

    SREC* record;

    if(strcmp(cmd2, "lname") == 0)
    {
        cmdNum = 1;
    }
    else if(strcmp(cmd2, "fname") == 0)
    {
        cmdNum = 2;
    }
    else if(strcmp(cmd2, "SID") == 0)
    {
        cmdNum = 3;
    }
    else if(strcmp(cmd2, "GPA") == 0)
    {
        cmdNum = 4;
    }
    else
    {
        printf("Unrecognized list: %s\n\n", cmd2);
        return 1;
    }

    /*send cmdNum to server*/
    n = write(sockfd, &cmdNum, sizeof(int));
    if (n < 0)
    { 
        printf("ERROR writing to socket/n");
    }   

    /*recieve numR from server*/
    n = read(sockfd, &numR, 255);
    if (n < 0) 
    {
        printf("ERROR reading from socket\n");
    }

    printf("| SID   | Lname     | Fname      | M | GPA  |\n+-------+-----------+------------+---+------+");

    for(i = 0; i < numR; i++)
    {
        /*send i to server to tell it position of repetition*/
        n = write(sockfd, &i, sizeof(int));

        /*receive ith record*/
        n = read(sockfd, record, sizeof(SREC));

        /*print record to screen*/
        printf("| %05lu | %9s | %9s | %c | %.2f |", record->SID, record->lname, record->fname, record->initial, record->GPA);               }

        printf("+-------+-----------+------------+---+------+\n");
    }

    return 0;
}

Answer 1

在你的行中：

printf("| %05lu | %9s | %9s | %c | %.2f |", record->SID, record->lname, record->fname, record->initial, record->GPA);               }

最后有一个}。一直向右滚动。

警告：控制到达非空函数的结束在用户定义的函数中

1 个答案: