将org.w3c.dom.Document打印到stdout的最短路径是什么?

时间:2010-02-24 10:58:27

标签: java xml dom w3c

org.w3c.dom.Document打印到stdout的最简单方法是什么?(a.k.a。格式化)?

6 个答案:

答案 0 :(得分:173)

调用printDocument(doc, System.out),该方法如下所示:

public static void printDocument(Document doc, OutputStream out) throws IOException, TransformerException {
    TransformerFactory tf = TransformerFactory.newInstance();
    Transformer transformer = tf.newTransformer();
    transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "no");
    transformer.setOutputProperty(OutputKeys.METHOD, "xml");
    transformer.setOutputProperty(OutputKeys.INDENT, "yes");
    transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
    transformer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "4");

    transformer.transform(new DOMSource(doc), 
         new StreamResult(new OutputStreamWriter(out, "UTF-8")));
}

indent-amount是可选的,可能不适用于您的特定配置)

答案 1 :(得分:13)

怎么样:

OutputFormat format = new OutputFormat(doc);
format.setIndenting(true);
XMLSerializer serializer = new XMLSerializer(System.out, format);
serializer.serialize(doc);

答案 2 :(得分:10)

使用一个班轮试试jcabi-xml

String xml = new XMLDocument(document).toString();

这是您需要的依赖项:

<dependency>
  <groupId>com.jcabi</groupId>
  <artifactId>jcabi-xml</artifactId>
  <version>0.14</version>
</dependency>

答案 3 :(得分:3)

private void printNode(Node rootNode, String spacer) {
    System.out.println(spacer + rootNode.getNodeName() + " -> " + rootNode.getNodeValue());
    NodeList nl = rootNode.getChildNodes();
    for (int i = 0; i < nl.getLength(); i++)
        printNode(nl.item(i), spacer + "   ");
}

答案 4 :(得分:1)

这将使用递归下降/上升返回格式良好的输出。

private static boolean skipNL;
private static String printXML(Node rootNode) {
    String tab = "";
    skipNL = false;
    return(printXML(rootNode, tab));
}
private static String printXML(Node rootNode, String tab) {
    String print = "";
    if(rootNode.getNodeType()==Node.ELEMENT_NODE) {
        print += "\n"+tab+"<"+rootNode.getNodeName()+">";
    }
    NodeList nl = rootNode.getChildNodes();
    if(nl.getLength()>0) {
        for (int i = 0; i < nl.getLength(); i++) {
            print += printXML(nl.item(i), tab+"  ");    // \t
        }
    } else {
        if(rootNode.getNodeValue()!=null) {
            print = rootNode.getNodeValue();
        }
        skipNL = true;
    }
    if(rootNode.getNodeType()==Node.ELEMENT_NODE) {
        if(!skipNL) {
            print += "\n"+tab;
        }
        skipNL = false;
        print += "</"+rootNode.getNodeName()+">";
    }
    return(print);
}

答案 5 :(得分:-1)

如果你使用dom4j,它将是dom4JDOM.asString()