Question

import java.util.Queue;
import java.util.Scanner;
import java.util.LinkedList;

class PalindromeTest 
{

    public static void main(String[] args) 
    {

           System.out.print("Enter any string:");
           Scanner in = new Scanner(System.in);
           String inputString = in.nextLine();
           Queue queue = new LinkedList();
           for (int i = inputString.length()-1; i >=0; i--) 
           {
               queue.add(inputString.charAt(i));
           }

           String reverseString = "";

           while (!queue.isEmpty()) 
           {
               reverseString = reverseString+queue.remove();
           }
           if (inputString.equals(reverseString))
              System.out.println("The input String is a palindrome.");
           else
              System.out.println("The input String is not a palindrome.");
    }
}

因此，如果字符串输入是Palindrome，则此代码打印输出，但不确定如何使其成为循环并在输入空行时终止。我尝试过while while循环，但没有运气

Answer 1

喜欢这样吗？

        System.out.print("Enter any string:");
        Scanner in = new Scanner(System.in);
        String inputString; //extract the inputString as a variable
        while (!(inputString = in.nextLine()).equals("")) //just add this loop, the rest is same as yours
        {
            Queue queue = new LinkedList();
            for (int i = inputString.length() - 1; i >= 0; i--)
            {
                queue.add(inputString.charAt(i));
            }

            String reverseString = "";

            while (!queue.isEmpty())
            {
                reverseString = reverseString + queue.remove();
            }
            if (inputString.equalsIgnoreCase(reverseString))
            {
                System.out.println("The input String is a palindrome.");
            }
            else
            {
                System.out.println("The input String is not a palindrome.");
            }
            System.out.print("Enter any string:");
        }

在用户在java中输入空行之前，我将如何进行此循环？

1 个答案: