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Question

我计算了桥梁的载荷，我希望使用最大似然估计将Gumbel的分布拟合到最高的20％。我需要帮助计算分布的参数。我已经阅读了scipy.optimize文档，但我无法理解如何在其中应用函数来估计两个参数函数。

以下是一些可能有所帮助的理论：存在两个似然函数（L1和L2），一个用于高于某个阈值的值（x> = C），一个用于低于（x

这里有我编写的一些代码：

non_truncated_data = ([15.999737471905252, 16.105716234887431, 17.947809230275304, 16.147752064149291, 15.991427126788327, 16.687542227378565, 17.125139229445359, 19.39645340792385, 16.837044960487795, 15.804473320190725, 16.018569387471025, 16.600876724289019, 16.161306985203151, 17.338636901595873, 18.477371969176406, 17.897236722220281, 16.626465201654593, 16.196548622931672, 16.013794215070927, 16.30367884232831, 17.182106070966608, 18.984566931768452, 16.885737663740024, 16.088051117522948, 15.790480003140173, 18.160947973898388, 18.318158853376037])

threshold = 15.78581825859324

def maximum_likelihood_function(non_truncated_loads, threshold, loc, scale):
    """Calculates maximum likelihood function's value for given truncated data
    with given parameters.
    Maximum likelihood function for truncated data is L1 * L2. Where L1 is a 
    product of multiplication of pdf values at non-truncated known values
    (non_truncated_values). L2 is a the probability that threshold value will
    be exceeded.
    """
        is_first = True
    # calculates L1
    for x in non_truncated_loads:
        if is_first:
            L1 = gumbel_pdf(x, loc, scale)
            is_first = False
        else:
            L1 *= gumbel_pdf(x, loc, scale)

    # calculates L2
    cdf_at_threshold = gumbel_cdf(threshold, loc, scale)
    L2 = 1 - cdf_at_threshold

    return L1*L2

def gumbel_pdf(x, loc, scale):
    """Returns the value of Gumbel's pdf with parameters loc and scale at x .
    """
    # exponent
    e = math.exp(1)
    # substitute
    z = (x - loc)/scale

    return (1/scale) * (e**(-(z + (e**(-z)))))

def gumbel_cdf(x, loc, scale):
    """Returns the value of Gumbel's cdf with parameters loc and scale at x.
    """
    # exponent
    e = math.exp(1)

    return (e**(-e**(-(x-loc)/scale)))

Answer 1

首先，使用scipy.optimize优化函数的最简单方法是构造目标函数，使得第一个参数是需要优化的参数列表，以下参数指定其他内容，例如作为数据和固定参数。

其次，使用numpy

提供的矢量化非常有用

因此我们有这些：

In [61]:
#modified pdf and cdf
def gumbel_pdf(x, loc, scale):
    """Returns the value of Gumbel's pdf with parameters loc and scale at x .
    """
    # substitute
    z = (x - loc)/scale

    return (1./scale) * (np.exp(-(z + (np.exp(-z)))))

def gumbel_cdf(x, loc, scale):
    """Returns the value of Gumbel's cdf with parameters loc and scale at x.
    """
    return np.exp(-np.exp(-(x-loc)/scale))
In [62]:

def trunc_GBL(p, x):
    threshold=p[0]
    loc=p[1]
    scale=p[2]
    x1=x[x<threshold]
    nx2=len(x[x>=threshold])
    L1=(-np.log((gumbel_pdf(x1, loc, scale)/scale))).sum()
    L2=(-np.log(1-gumbel_cdf(threshold, loc, scale)))*nx2
    #print x1, nx2, L1, L2
    return L1+L2
In [63]:

import scipy.optimize as so
In [64]:
#first we make a simple Gumbel fit
so.fmin(lambda p, x: (-np.log(gumbel_pdf(x, p[0], p[1]))).sum(), [0.5,0.5], args=(np.array(non_truncated_data),))
Optimization terminated successfully.
         Current function value: 35.401255
         Iterations: 70
         Function evaluations: 133
Out[64]:
array([ 16.47028986,   0.72449091])
In [65]:
#then we use the result as starting value for your truncated Gumbel fit
so.fmin(trunc_GBL, [17, 16.47028986,   0.72449091],  args=(np.array(non_truncated_data),))
Optimization terminated successfully.
         Current function value: 0.000000
         Iterations: 25
         Function evaluations: 94
Out[65]:
array([ 13.41111111,  16.65329308,   0.79694   ])

在trunc_GBL函数中，我用缩放的pdf

替换了你的pdf

enter image description here

请参阅此处的基本原理，主要是因为您的L1是基于pdf的，而L2是基于cdf的：http://support.sas.com/documentation/cdl/en/statug/63033/HTML/default/viewer.htm#statug_lifereg_sect018.htm

然后我们注意到一个问题：在最后一个输出中看到Current function value: 0.000000。负对数似然函数为0.

这是因为：

In [66]:

gumbel_cdf(13.41111111,  16.47028986,   0.72449091)
Out[66]:
2.3923515777163676e-30

有效0.这意味着根据您刚才描述的模型，当阈值足够低时，总是达到最大值，以使L1非exsit（x < threshold为空）和{{对于数据中的所有项目，1}}为1（L2为1-F(C)。

出于这个原因，你的模型看起来并不适合我。你可能想重新考虑一下。

修改

我们可以进一步隔离1并将其视为固定参数：

threshold

以不同的方式调用优化器：

def trunc_GBL(p, x, threshold):
    loc=p[0]
    scale=p[1]
    x1=x[x<threshold]
    nx2=len(x[x>=threshold])
    L1=(-np.log((gumbel_pdf(x1, loc, scale)/scale))).sum()
    L2=(-np.log(1-gumbel_cdf(threshold, loc, scale)))*nx2
    #print x1, nx2, L1, L2
    return L1+L2

这样，如果您想要70％分位数，您只需将其更改为so.fmin(trunc_GBL, [0.5, 0.5], args=(X, np.percentile(X, 20))) Optimization terminated successfully. Current function value: 20.412818 Iterations: 72 Function evaluations: 136 Out[9]: array([ 16.34594943, 0.45253201])，依此类推。 np.percentile(X, 30)只是执行np.percentile()

的另一种方式

如何使用scipy.optimize查找gumbel分布的参数

1 个答案:

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