Question

John 5555

Nancy 5555

Joe 2323

我需要一个简单查询的示例来执行以下操作，以便我可以弄清楚如何操作将其应用于另一个查询。 THX。

 Search for "John"
 Returns rows John, Nancy

 Search for "Nancy"
 Returns rows John, Nancy

 Search for "Joe"
 Returns rows Joe

这是我到目前为止所做的：

$query = mysqli_query($connect," SELECT *
FROM users
WHERE name like '%$search%'
   (   SELECT number 
      FROM users
      WHERE number like number )
ORDER BY date ASC");

Answer 1

你可以试试这个：

假设您的table列名称和号码。

name  |  number
John  |   5555
Nancy |   5555
Joe   |   2323

以下是代码：

<?php

/* ESTABLISH CONNECTION */

$connection=mysqli_connect("YourHost","Username","Password","DatabaseName");

if(mysqli_connect_errno()){

echo "Error".mysqli_connect_error();
}

if(isset($_POST['submitsearch'])){ /* IF FORM IS SUBMITTED */
   $searchname=mysqli_real_escape_string($connection,$_POST['search']); /* PREVENT SOME OF THE SQL INJECTIONS */
   $result=mysqli_query($con,"SELECT * FROM table WHERE name='$searchname'");
   while($row=mysqli_fetch_array($result)){
   $number=mysqli_real_escape_string($connection,$row['number']); /* GET THE RESPECTIVE NUMBER OF THE SEARCHED NAME */
   }


   /* ECHO THE RESULT HERE */
   echo "<table>";
   $result2=mysqli_query($con,"SELECT * FROM table WHERE number='$number'");
   while($row2=mysqli_fetch_array($result)){ /* FETCH ROWS WITH THE SAME NUMBER COLUMN */
   echo "<tr><td>".$row2['name']."</td></tr>";
   }
   echo "</table>";

}

/* THIS IS YOUR HTML FORM */

echo "<form action='' method='POST'>"; /* SUBMIT ON THE SAME PAGE */
echo "search:<input type='text' name='search'>";
echo "<input type='text' value='search' name='submitsearch'>";
echo "</form>";

?>

Answer 2

如果我不错过你的要求，你的sql语句应该是这样的：

$sql ="SELECT * FROM user WHERE name LIKE '%$search%' 
OR number IN(SELECT number FROM user WHERE name LIKE '%$search%') 
ORDER BY Date ASC";
$query = mysqli_query($connect,$sql);

希望这对你有所帮助。

简单的子查询？

2 个答案: