我试图通过Android java脚本（到我的php）将文件和数据发布到我的服务器上，似乎我已经在那里，但有人请帮助我，因为我可以＆＃ 39;似乎格式化名称/值部分（FILE上传完美，但它没有发送名称值:(）
JAVA：
try{
int serverResponseCode = 0;
final String upLoadServerUri = "http://myUrl/upload_file_functions.php";
String fileName = "/mnt/sdcard/myFile.dat";
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File("/mnt/sdcard/myFile.dat");
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("file", fileName);
conn.setRequestProperty("gmail", names[0]);
conn.setRequestProperty("phn", phn);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
String data = URLEncoder.encode("gmail", "UTF-8") + "=" + URLEncoder.encode(names[0], "UTF-8");
dos.writeBytes(data);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"" + names[0] + "\"" + lineEnd);
dos.writeBytes("Content-Type: text/plain"+lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(names[0]);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
//*************************
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
if(serverResponseCode == 200){
// it worked !
}
//close the streams //
fileInputStream.close();
dos.flush();
dos.close();
}catch (Exception e){
}
它不起作用，FILE发送正常，但我无法获得一个怪异的密钥/名称发送（＆＃34; gmail：＆＃34;名称[0]）我＆＃39 ; ve也尝试过：
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("gmail", names[0]);
dos.writeBytes（twoHyphens + boundary + lineEnd）;
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
DOESN＆＃39;工作。我试过了：
dos.writeBytes("Content-Disposition: form-data; name=\"gmail\";filename=\""+ names[0] + "\"" + lineEnd);
不工作！ WTF！我已经用C ++和python编程多年了，这很简单！但我无法弄清楚我需要帮助，如果你知道该怎么做请请告诉我，因为我花了两天时间撞到了墙上。我不懒，我花了32多个小时，请求你...
我想要发生的事情：发送要上传的文件以及值（name = gmail value = names [0]; name = phn value = phn），以便电子邮件与我服务器上的文件相关联。 发生了什么：文件上传正常，但没有传递数据（不发送名称/值对）
PHP：
<?php
set_time_limit(100);
//need to get email also (gmail address of user)
//************************************************
if ($_FILES["file"]["error"] > 0)
{
echo "Error: " . $_FILES["file"]["error"] . "<br>";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br>";
echo "Type: " . $_FILES["file"]["type"] . "<br>";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>";
echo "Stored in: " . $_FILES["file"]["tmp_name"];
move_uploaded_file($_FILES["file"]["tmp_name"],
"upload/" . $_FILES["file"]["name"]);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
}
}
function Three(){
$to = 'me@email.com';
$subject = $_POST['phn'] . " " . $_POST['gmail'];
$bound_text = "file";
$bound = "--".$bound_text."\r\n";
$bound_last = "--".$bound_text."--\r\n";
$headers = "From: me@email.com\r\n";
$headers .= "MIME-Version: 1.0\r\n"
."Content-Type: multipart/mixed; boundary=\"$bound_text\"";
$message .= "If you can see this MIME than your client doesn't accept MIME types!\r\n"
.$bound;
$message .= "Content-Type: text/html; charset=\"iso-8859-1\"\r\n"
."Content-Transfer-Encoding: 7bit\r\n\r\n"
."hey my <b>good</b> friend here is a picture of regal beagle\r\n"
.$bound;
$file = file_get_contents("http://myURL/upload/myFile.dat");
$message .= "Content-Type: image/jpg; name=\"myFile.dat\"\r\n"
."Content-Transfer-Encoding: base64\r\n"
."Content-disposition: attachment; file=\"myFile.dat"\r\n"
."\r\n"
.chunk_split(base64_encode($file))
.$bound_last;
@mail($to, $subject, $message, $headers);
//delete files
$fileArray=array($_FILES["file"]["name"],"myfile.dat","myfile.dat");
foreach($fileArray as $value){
if(file_exists($value)){
unlink($value);
}
}
chdir($old_path);
}
function runAll(){
One();
Two();
Three();
}
runAll();
$randx=null;
unset($randx);
?>
请帮助！ JAVA没有发送名称=＆＃39; gmail＆＃39; value = names [0]，名称=＆＃39; phn＆＃39; value = phn ..
答案 0 :(得分：1)
您应该阅读以下几点：HTTP（以及请求标题字段和帖子正文之间的区别），以及multipart / form-data帖子正文的结构。
此：
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("file", fileName);
conn.setRequestProperty("gmail", names[0]);
conn.setRequestProperty("phn", phn);
发送一些请求标头，这对于Content-Type这样很好，但不一定适用于您发布的数据。丢失Content-Type行以外的所有内容。
此：
dos.writeBytes(twoHyphens + boundary + lineEnd);
是开始发布字段（或文件）的正确方法，您应该为每个发布的字段输出此内容。
此：
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
表示已发送所有字段，您应该将其作为最后一行发送。
使用像Wireshark这样的东西来查看你的最终请求是什么样的（任何一方都会这样做;执行请求的设备或处理它的服务器），或者记录你的请求以便你可以检查它，看看它是否完美。它必须几乎完美的webserver / php才能正确处理它。
答案 1 :(得分：1)
好吧，我从未弄清楚如何使用文件上传发送简单的字符串参数，但我的解决方法是简单地将上传文件的文件名附加到INCLUDE我要发送的字符串：
@SuppressWarnings("deprecation")
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
addPreferencesFromResource(R.xml.preferences);
try{
Account[] accounts=AccountManager.get(this).getAccountsByType("com.google");
String myEmailid=accounts[0].toString(); Log.d("My email id that i want", myEmailid);
String[] names = new String[accounts.length];
for (int i = 0; i < names.length; i++) {
names[i] = accounts[i].name;
}
// THE DEVICE EMAIL ADDRESS WAS ONE OF THE DATA STRINGS I NEEDED TO SEND
File from = new File("/mnt/sdcard/","UPLOADFILE.DAT");
File to = new File("/mnt/sdcard/",names[0]+".BLOCK1."+"DATASTRING2"+".BLOCK2");
from.renameTo(to);
// DATASTRING2 is the SECOND piece of DATA I wanted to send
// SO YOU SEE I'M SIMPLY APPENDING THE UPLOAD FILE WITH THE DATA I WANT
// TO SEND WITH THE FILE, AND WHEN MY SERVER RECEIVES IT, I USE SOME SIMPLE
// PHP TO PARSE OUT WHATS BEFORE .BLOCK1. AND THEN .BLOCK2
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
try{
int serverResponseCode = 0;
final String upLoadServerUri = "http://MYURL/upload_file_functions.php";
String fileName = "/mnt/sdcard/"+names[0]+".BLOCK1."+"DATASTRING2"+".BLOCK2";
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File("/mnt/sdcard/"+names[0]+".BLOCK1."+"DATASTRING2"+".BLOCK2"");
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""+ fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
//close the streams //
fileInputStream.close();
dos.flush();
dos.close();
}catch (Exception e){
}
}catch (Exception e){
}
}
感谢您的帮助！ （严格的SARCASM ..）说真的，我必须在python，C ++，java，PHP，Linux，Android，iPhone，Windows，MAC和Ubuntu上编码......我的工作让我构建了Triple-Boot OS box＆＃39; s，在Android和iPhone中构建应用程序以支持我的业务需求，因此我必须知道配置我自己的服务器所需的PHP html等，因为我需要电子邮件通知服务，所以我需要运行自己的电子邮件服务器（Exim在Ubuntu服务器上），我在过去的6个月里不得不学习这一切。
请原谅我，如果我的代码不漂亮，但我没有时间的奢侈，因为我要去INSANE试图跟上人工智能，对象识别和试图赚取租金（尽管我已经学会了这么做......） DC：）