很抱歉再次提起这件事。当我第一次开始开发我的Android应用程序时,我正在使用HttpClient。我意识到谷歌正式将这个类弃用于最新版本的Android;他们鼓励开发人员使用HttpUrlConnection。
当我尝试将文件(JPEG)上传到我在GAE上托管的PHP Server API时,我最近遇到了问题。我花了很多精力来使用Multipart来实现这一目标。我最终使用了以下课程。但它仍然不能用于一些未知的原因。我的PHP Server API成功接收了我的POST数据但无法接收我的文件。我的代码出了什么问题?
如果您想知道,我可以使用isset($_FILES["profile_picture"])
验证我是否收到了与我的服务器无关的信息。
这是我的班级:
package net.XXXXX;
import android.util.Log;
import java.io.BufferedInputStream;
import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLConnection;
import java.util.ArrayList;
import java.util.List;
import javax.net.ssl.HttpsURLConnection;
public class MultipartUtility {
private HttpURLConnection mConnection;
private OutputStream outputStream;
private PrintWriter mWriter;
private final String boundary;
private static final String LINE_FEED = "\r\n";
private final static String CHARSET = "UTF-8";
private final static String API_URL = "https://select-connection.appspot.com/";
public static final String LOG_TAG = "APIRequestHandler";
public static final int CONNECT_TIMEOUT = 15000;
public static final int READ_TIMEOUT = 10000;
/**
* ...
*/
public MultipartUtility() throws IOException {
// creates a unique boundary based on time stamp.
boundary = "===" + System.currentTimeMillis() + "===";
URL url = new URL(API_URL);
mConnection = (HttpsURLConnection)url.openConnection();
mConnection.setConnectTimeout(CONNECT_TIMEOUT);
mConnection.setReadTimeout(READ_TIMEOUT);
mConnection.setRequestMethod("POST");
mConnection.setRequestProperty("Accept-Charset", "UTF-8");
mConnection.setRequestProperty("Accept", "application/json");
mConnection.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + boundary);
mConnection.setUseCaches (false);
mConnection.setDoInput(true);
mConnection.setDoOutput(true);
outputStream = mConnection.getOutputStream();
mWriter = new PrintWriter(new OutputStreamWriter(outputStream, CHARSET), true);
}
/**
* ...
*/
public void addFormField(String name, String value) {
mWriter.append("--" + boundary).append(LINE_FEED)
.append("Content-Disposition: form-data; name=\"" + name + "\"")
.append(LINE_FEED)
.append("Content-Type: text/plain; charset=" + CHARSET)
.append(LINE_FEED)
.append(LINE_FEED)
.append(value)
.append(LINE_FEED);
mWriter.flush();
}
/**
* ...
*/
public void addFilePart(String fieldName, File uploadFile)
throws IOException {
String fileName = uploadFile.getName();
mWriter.append("--" + boundary).append(LINE_FEED)
.append("Content-Disposition: form-data; name=\"" + fieldName + "\"; filename=\"" + fileName + "\"")
.append(LINE_FEED)
.append("Content-Type: " + URLConnection.guessContentTypeFromName(fileName))
.append(LINE_FEED)
.append("Content-Transfer-Encoding: binary")
.append(LINE_FEED)
.append(LINE_FEED);
mWriter.flush();
FileInputStream inputStream = new FileInputStream(uploadFile);
byte[] buffer = new byte[4096];
int bytesRead;
while ((bytesRead = inputStream.read(buffer)) != -1) {
outputStream.write(buffer, 0, bytesRead);
}
outputStream.flush();
inputStream.close();
mWriter.append(LINE_FEED);
mWriter.flush();
}
/**
* ...
*/
public void addHeaderField(String name, String value) {
mWriter.append(name + ": " + value).append(LINE_FEED);
mWriter.flush();
}
/**
* ...
*/
public String finish() throws IOException {
String response;
mWriter.append(LINE_FEED).flush();
mWriter.append("--" + boundary + "--").append(LINE_FEED);
mWriter.close();
// checks server's status code first
int status = mConnection.getResponseCode();
if (status == HttpURLConnection.HTTP_OK) {
response = ApiRequestHandler.convertStreamToString(new BufferedInputStream(mConnection.getInputStream()));
mConnection.disconnect();
} else {
throw new IOException("Server returned non-OK status: " + status);
}
return response;
}
}
这就是我使用它的方式:
try {
MultipartUtility connection = new MultipartUtility();
connection.addFormField("action", "update_picture");
connection.addFormField("user_id", mUserId);
connection.addFormField("session_token", mSessionToken);
connection.addFilePart("profile_picture", mProfilePicture);
String result = connection.finish();
Log.d("PROFILE PICTURE", result);
} catch (IOException e) {
e.printStackTrace();
}
答案 0 :(得分:1)
需要多部分吗?如果您只需要使用POST请求发送一个文件,则只需将其二进制数据写入连接的输出流即可。 (我没有使用PHP的经验,但我认为PHP将能够读取请求体)。其他字段可以作为查询参数或HTTP标头进行传输。
我还建议通过Fiddler2等日志代理路由HTTP流量,以查看HTTP请求正文中的实际内容(并将其与工作测试示例进行比较)。
答案 1 :(得分:0)
我终于找到了问题。谢谢mjn为我提供了Fiddler2 Web调试解决方案。使用这个软件,我能够编写一个有效的HTTP请求来测试我的服务器API。这个问题与我的代码无关。 PHP无法接收上传文件的原因是因为Google App Engine会自动拒绝每个上传的文件。要上传文件,您需要先创建一个上传网址。
来源:https://cloud.google.com/appengine/docs/php/googlestorage/user_upload