Question

我已经制作了一个代码来计算电路中的电阻。它考虑了系列之间的每个变化＆＃39;并且＆＃39;并行＆＃39;然后给出部件数量，每个部件的电阻器数量和每个电阻器的电阻。

def resistance():
    p = int(input('Enter number of parts. One "part" is a resistor or sequence of resistors that are in parallel while the rest are in series, or vice versa.'))
    for x in range(1, p):
        n = input('Enter number of resistors in part' + x)
        for y in range(1, n):
            w = input('Enter the resistance of resistor #' + y)
            q.append(w)
        t = str(input('In series or parallel? Enter S for series, P for parallel.'))
        if t == 'S':
            for z in range(1, len(q)):
                s += q[z-1]
        elif t == 'P':
            for v in range(1, len(q)):
                s += (1/q[z-1])
        q = []
    return s

问题是，无论何时我运行它都会接收到＆＃39;然后会出现以下错误：

本地变量＆＃39;在分配前引用

当我在第一个循环之前设置s = 0时，它只需要输入＆＃39; p＆＃39;然后返回0。

谁能告诉我哪里出错了？

编辑：上述问题已经解决，但现在又出现了问题。代码如下：

def resistance():
s = 0
q = []
p = int(input('Enter number of parts. One "part" is a resistor or sequence of resistors that are in parallel while the rest are in series, or vice versa. '))
p += 1
for x in range(1, p):
    n = int(input('Enter number of resistors in part ' + str(x) + ':'))
    n += 1
    for y in range(1, n):
        w = input('Enter the resistance of resistor #' + str(y) + ', in ohms:')
        q.append(w)
    t = str(input('In series or parallel? Enter S for series, P for parallel. '))
    if t == 'S':
        for z in range(1, len(q)+1):
            s += int(q[z-1])
    elif t == 'P':
        for v in range(1, len(q)+1):
            s += int(1/int(q[z-1]))
    q = []
return s

它是串联工作，但同时它说： - 虽然我在＆＃39;系列中做了几乎相同的事情＆＃39;部分，那里没有错误。将不胜感激。

Answer 1

在您的代码中，您需要更改一些内容，首先初始化变量s=0和列表q = []。使用输入时，它会尝试添加字符串'enter ...'和整数x,y，如果您希望它添加两个整数，则将n定义为

n = input('input number')+x，结果是两个加的整数。此外，当您对串行或并行执行输入时，您将收到一条错误，指出S未定义或P未定义，您可以使用raw_input来解决此问题，并将S或P输入转换为字符串。这是代码：

def resistance():
    s = 0
    q = []
    p = int(input('Enter number of parts. One "part" is a resistor or sequence of resistors that are in parallel while the rest are in series, or vice versa. '))
    for x in range(1, p):
        n = input('Enter number of resistors in part ')+x
        for y in range(1, n):
            w = float(input('Enter the resistance of resistor # '))+y
            q.append(w)
        t = raw_input('In series or parallel? Enter S for series, P for parallel. ')
        if t == 'S':
            for z in range(1, len(q)):
                s += q[z-1]
        elif t == 'P':
            for v in range(1, len(q)):
                s += (1/q[v-1])
        q = []
    return s

def test():
   print resistance()
if __name__=='__main__':
    test()

Python代码无法正常工作

1 个答案: