Question

...我有一个在shell中运行的scrapy代码，但是当我尝试将其导出到csv时，它会返回一个空文件。当我没有进入链接并尝试解析描述时，它会导出数据

    import scrapy

class DmozSpider(scrapy.Spider):
    name = "dmoz"
    allowed_domains = ["dmozs.org"]
    start_urls = [
        "http://www.dmoz.org/Computers/Programming/Languages/Python/Books/",
        "http://www.dmoz.org/Computers/Programming/Languages/Python/Resources/"
    ]

    def parse(self, response):
        filename = response.url.split("/")[-2] + '.html'
        with open(filename, 'wb') as f:
            f.write(response.body)

Answer 1

import scrapy

class DmozSpider(scrapy.Spider):
    name = "dmoz"
    allowed_domains = ["dmoz.org"]
    start_urls = [
        "http://www.dmoz.org/Computers/Programming/Languages/Python/Books/",
        "http://www.dmoz.org/Computers/Programming/Languages/Python/Resources/"
    ]

    def parse(self, response):
        filename = response.url.split("/")[-2] + '.html'
        with open(filename, 'wb') as f:
            f.write(response.body)

只是你错过了类型 allowed_domains = [＆＃34; dmozs.org＆＃34;] allowed_domains = [＆＃34; dmoz.org＆＃34;]

Answer 2

请更改代码allowed_domains = ["dmoz.org"]

scrapy代码无法正常工作

2 个答案: