Question

我有这份清单

a = [['c', '1.3e-8', '4.5e-8'], ['h', '3.4e-5', '2.3e-7', '2.3e-5']]

我想格式化＆＃39; e＆＃39;字符串仅作为

a = [[ 'c', '0.000000013', '0.000000045'], ['h', '0.000034', '0.00000023', '0.000023']]

我怎样才能在Python中执行此操作？谢谢！

Answer 1

如果你确定只有第一个元素不是浮点数。

from decimal import Decimal

a = [['c', '1.3e-8', '4.5e-8'], ['h', '3.4e-5', '2.3e-7', '2.3e-5']]

for inx, rec in enumerate(a):
    a[inx] = [rec[0]] + ['{:.{precise}f}'.format(Decimal(val),
                precise=int(val[-1])+1) for val in rec[1:]]

print(a)

输出：

[['c', '0.000000013', '0.000000045'], ['h', '0.000034', '0.00000023', '0.000023']]

格式化列表列表中的字符串

1 个答案: