Question

我有这个按钮和工作的Switch指令。问题是，当我点击名为“Koala”的案例时，当我只想要其中一个时，就会发生2个动作。我该如何解决这个问题？

private void KinectTileButtonClick(object sender, RoutedEventArgs e)
{
    var button = (KinectTileButton)e.Source;
    switch (button.Label.ToString())
    {
        case "Koala2":
            KinectTileButton_Click_1(sender, e);

            break;

    }
    var wineModel = button.Tag as WineModel;
    var selectionDisplay = new SelectionDisplay(wineModel);
    this.kinectRegionGrid.Children.Add(selectionDisplay);

    e.Handled = true;
}

Answer 1

我相信您只是不希望执行测试后的操作：

所以你可以在测试中添加一个回报。

休息不会帮助你“走出方法”，它只是为了转换。

private void KinectTileButtonClick(object sender, RoutedEventArgs e)
{
    var button = (KinectTileButton)e.Source;
    if(button.Label.ToString() == "Koala2")
    {
            KinectTileButton_Click_1(sender, e);
            return;//get out of this method.
    }
    var wineModel = button.Tag as WineModel;
    var selectionDisplay = new SelectionDisplay(wineModel);
    this.kinectRegionGrid.Children.Add(selectionDisplay);

    e.Handled = true;
}

或使用if / else

private void KinectTileButtonClick(object sender, RoutedEventArgs e)
    {
        var button = (KinectTileButton)e.Source;
        if(button.Label.ToString() == "Koala2")
                KinectTileButton_Click_1(sender, e);
        else  
        {
            var wineModel = button.Tag as WineModel;
            var selectionDisplay = new SelectionDisplay(wineModel);
            this.kinectRegionGrid.Children.Add(selectionDisplay);
        }
        e.Handled = true;
    }

顺便说一句，它可能更干净（好吧，我喜欢小方法）

private void KinectTileButtonClick(object sender, RoutedEventArgs e)
{
    var button = (KinectTileButton)e.Source;
    if(button.Label.ToString() == "Koala2")
       Method1(<somearguments>);
    else
       Method2(button.Tag as WineModel);

    e.Handled = true;//if it must happen for all label values.
}

public void Method1(<some parameters>) {
  //DoSomething
}

public void Method2(WineModel wineModel) {
  var selectionDisplay = new SelectionDisplay(wineModel);
    this.kinectRegionGrid.Children.Add(selectionDisplay);
}

执行单个开关箱

1 个答案: