Question

我目前正在撰写一份SQL语句，要求我列出工作时间比平均工作时间长的工人。这是我目前的代码：

Select T.TotalCandy,Sum(T.Amountofcandy) "Total Candy"
From ToralChocolate 
Inner Join Ompaloompa O 
On T.CandyNo = O.CandyNo and T.BoatNO = O.BoatNo 
Inner Join Transport TR
On TR.Transport = T.Transport 
Having Sum(T.AmountofCandy) > (Select Avg(AmountofCandy) from TotalChocolate)
Group By T.TotalCandy
Order By 1;

我在with语句中的子查询中遇到了我的问题，因为我将它与工作时的平均工作时间进行比较，而不是工作小时数的平均值！

任何帮助都将不胜感激。

Answer 1

Select W.WrkName,Sum(TI.HrsWorked) "Total Hours"
From Timelog TI 
Inner Join Allocation A 
On TI.WrkID = A.WrkID and TI.TaskID = A.TaskID 
Inner Join Worker W 
On TI.WrkID = W.WrkID 
Group By W.WrkName
Having Sum(TI.HrsWorked) > (Select Avg(HrsWorked) from Timelog)
Order By 1;

在团队之后拥有条款！

Answer 2

Select W.WrkName,Sum(TI.HrsWorked) "Total Hours"
From Timelog TI 
Inner Join Allocation A 
On TI.WrkID = A.WrkID and TI.TaskID = A.TaskID 
Inner Join Worker W 
On TI.WrkID = W.WrkID 
Group By W.WrkName
Having Sum(TI.HrsWorked) > 
    (Select Avg(HrsWorked) 
     From 
        (Select WrkID, SUM(HrsWorked) As HrsWorked 
         From Timelog
         Group By WrkID)
    )
Order By 1;

你有没有尝试过类似的东西？

使用必须找到平均值

2 个答案: