Question

我缩放并将图像绘制为较小的图像。两个图像的原点是左上角（0,0）。较大的图像是100x100px（但可以是任何大小），较小的图像是28x28px。那部分很容易，28/100 =比例因子

接下来的部分是我希望通过缓慢缩小比例因子来缩小图像尺寸，但我希望图像在28x28px框中保持居中，所以问题是，如何计算x和y偏移以根据缩放系数使对象居中于28x28框中？

function scale(scalefactor as float,destregion as object, sourceregion as object) as object
    sourceregion.setalphaenable(true)
    destregion.setalphaenable(true)
    destregion.setscalemode(1)
    destregion.clear(&h00000000)

    xOffset= ****** getStackOverFlowHelp(???) ******
    yOffset= ****** getSTackOverflowHelp(???) ******

    destregion.drawscaledobject(xOffset,yOffset,scalefactor,scalefactor,sourceregion)
    destregion.finish()
end function

Answer 1

令人尴尬的是，我在这里找到了答案：的 Math to center an image on a screen

虽然背景不同......

工作职能：

function scale(scalefactor as float,destregion as object,sourceregion as object) as object sourceregion.setalphaenable(true) destregion.setalphaenable(true) destregion.setscalemode(1) destregion.clear(&h00000000) ww=sourceregion.getwidth()*scalefactor w=destregion.getwidth() hh=sourceregion.getwidth()*scalefactor h=destregion.getwidth() xOffset=(w/2)-(ww/2) yoffset=(h/2)-(hh/2) destregion.drawscaledobject(xOffset,yOffset,scalefactor,scalefactor,sourceregion) destregion.finish() end function

当缩放和原点在左上方时，保持图像居中

1 个答案: