Question

好的，到目前为止，我一直在摸不着头脑;很抱歉这个很长的问题......

我使用这个Lucene Query Parser来解析产生这种数据结构的字符串/查询：

// Notice that the repetition of 'field3' is on purpose
Sample String: field1:val1 AND field2:val2 OR field3:val3 AND field3:val4
Result:
    { left: { field: "field1", term: "val1" },
      operator: "AND"
      right: {
          left: { field: "field2", term: "val2" },
          operator: "OR"
          right: { 
              left: {field: "field3", term: "val3" },
              operator: "AND",
              right: {
                   field: "field3",
                   term: "val4"
              }
          }
      }

我需要迭代该对象以获得以下内容：

[ [{ field: "field1", term: "val1"},
   { field: "field2", term: "val2"}
  ],
  [{ field: "field3", term: "val3"},
   { field: "field3", term: "val4"}
  ]
]

如果我试着解释一下，我的想法是创建一个数组数组，其中每个子数组用“OR”分隔，而子数组中的每个对象代表“AND”分隔的字段;虽然我认为上面的代码比我更好地解释了它

更新了代码（coffeescript和lo-dash，抱歉）：

groups = []     
createGroups = (item, previousGroup, previousOperator) ->
    currentGroup = if _.isArray previousGroup then previousGroup else []

    # keyVal = {}
    # keyVal[item.left?.field or item.field] =  item.left?.term or item.term
    obj = fieldName: item.left?.field or item.field, val: item.left?.term or item.term

    if previousOperator?.toUpperCase() is 'AND'
        currentGroup.push obj
    else
        currentGroup = [obj]

    if _.isObject item.right
        createGroups(item.right, currentGroup, item.operator)

    groups.push currentGroup

这段代码很有用，几乎可以做我想要的，但依赖于groups数组在函数外部声明（精细），但直接在函数内部使用，这不是很理想，但我可以忍受它。

但是，它会像这样复制每个组：

[ [ {field: "field1", val:val1}, {field: "field2" val:val2} ], [ {field: "field1":val1}, {field: "field2", val:val2} ], ...]

现在我必须使用_.uniq(groups)这是我不应该做的操作，如果上面的函数会返回正确的结果

感谢您的帮助

Answer 1

我认为应该这样做：

createGroups = (item, previousGroup) ->
  subroutine = (item, previousGroup) ->
    if typeof item is "object"
      unless item.operator
        if !item.left
          previousGroup.push item  
        else
          previousGroup.push item.left
        previousGroup
      if item.operator is "AND"
        currentGroup = subroutine(item.left, previousGroup)
        currentGroup = subroutine(item.right, currentGroup)
        currentGroup and groups.push(currentGroup)
      if item.operator is "OR"
        currentGroup = subroutine(item.left, previousGroup)
        groups.push currentGroup
        currentGroup and subroutine(item.right, [])
    return

  previousGroup = previousGroup or []
  subroutine item, previousGroup
  groups

createGroups o

Javascript嵌套对象到多维数组的递归函数

1 个答案: