这是我的疑问:
SELECT DISTINCT
ca.id_number,
CONVERT(VARCHAR(19),MAX(ca.creation_time),120) as creation_time,
CONVERT(VARCHAR(19),MAX(cc.close_date),120) as close_date,
cc.summary
FROM dbo.table_case ca
INNER JOIN table_case_display cd on cd.id_number = ca.id_number
INNER JOIN table_act_entry acte on ca.objid = acte.act_entry2case
INNER JOIN table_gbst_elm elm on elm.objid = acte.entry_name2gbst_elm
LEFT JOIN table_close_case cc on acte.objid = cc.close_case2act_entry
WHERE
"cd"."creation_time">={ts '2004-09-30 19:58:21'}
AND "ca"."id_number"<>'001'
AND ( "cd"."severity"='A'
OR "cd"."severity"='B'
OR "cd"."severity"='C'
OR "cd"."severity"='E'
OR "cd"."severity"='TBD')
AND "cd"."site_name"='Nextel International (Hosting)'
AND (ca.creation_time>={ts '2014-03-01 00:00:00'} AND ca.creation_time<{ts '2014-04-10 00:00:01'})
GROUP BY ca.creation_time, cc.close_date, ca.id_number, cc.summary
ORDER BY ca.id_number asc
这是输出:
C00001 2014-03-10 20:35:17 NULL NULL
C00002 2014-03-11 03:16:01 NULL NULL
C00002 2014-03-11 03:16:01 2014-03-11 18:10:41 test
C00003 2014-03-07 02:53:22 NULL NULL
C00003 2014-03-07 02:53:22 2014-03-12 18:41:59 test
从上面的输出中,它显示了重复的ID。 如何编写查询以避免此问题?
答案 0 :(得分:0)
更改
GROUP BY ca.creation_time, cc.close_date, ca.id_number, cc.summary
在
GROUP BY ca.id_number, cc.summary