我有以下代码用节点绘制图形,但我很想添加一个合适的图例: (对不起,我无法发布图像,似乎我没有声誉)
我想要一个带有4种颜色的传奇,例如"浅蓝色=过时,红色=草稿,黄色=发布,深蓝色=初始化"。
我已经看到了一些解决方案" scatter"但我觉得它太复杂了。有没有办法用" plt.legend(G.nodes)"?
感谢您的帮助!!
以下是代码:
import networkx as nx
import matplotlib.pyplot as plt
import numpy as np
G=nx.Graph()
G.add_node("kind1")
G.add_node("kind2")
G.add_node("Obsolete")
G.add_node("Draft")
G.add_node("Release")
G.add_node("Initialisation")
val_map = {'kind1': 2,'kind2': 2,'Obsolete': 2,'Initialisation': 1,'Draft': 4,'Release': 3}
values = [val_map.get(node, 0) for node in G.nodes()]
nodes = nx.draw(G, cmap = plt.get_cmap('jet'), node_color = values)
plt.legend(G.nodes())
plt.show()
答案 0 :(得分:4)
使用nx.draw时似乎存在某种错误。尝试使用nx.draw_networkx。 然后使用matplotlib中的轴在绘制图形时传递它。该轴应包含节点的标签和颜色,同时绘制(0,0) - >中的点。这是棘手的部分。
希望它有所帮助!这是我运行的代码:
import networkx as nx
import matplotlib.pyplot as plt
import numpy as np
# For color mapping
import matplotlib.colors as colors
import matplotlib.cm as cmx
G=nx.Graph()
G.add_node("kind1")
G.add_node("kind2")
G.add_node("Obsolete")
G.add_node("Draft")
G.add_node("Release")
G.add_node("Initialisation")
# You were missing the position.
pos=nx.spring_layout(G)
val_map = {'kind1': 2,'kind2': 2,'Obsolete': 2,'Initialisation': 1,'Draft': 4,'Release': 3}
values = [val_map.get(node, 0) for node in G.nodes()]
# Color mapping
jet = cm = plt.get_cmap('jet')
cNorm = colors.Normalize(vmin=0, vmax=max(values))
scalarMap = cmx.ScalarMappable(norm=cNorm, cmap=jet)
# Using a figure to use it as a parameter when calling nx.draw_networkx
f = plt.figure(1)
ax = f.add_subplot(1,1,1)
for label in val_map:
ax.plot([0],[0],
color=scalarMap.to_rgba(val_map[label]),
label=label)
# Just fixed the color map
nx.draw_networkx(G,pos, cmap = jet, vmin=0, vmax= max(values),
node_color=values,
with_labels=False,ax=ax)
# Here is were I get an error with your code
#nodes = nx.draw(G, cmap = plt.get_cmap('jet'), node_color = values)
# Setting it to how it was looking before.
plt.axis('off')
f.set_facecolor('w')
plt.legend(loc='center')
f.tight_layout()
plt.show()
一些有用的资料来源:
[1] http://pydoc.net/Python/networkx/1.0.1/networkx.drawing.nx_pylab/
[2] http://matplotlib.org/api/legend_api.html
答案 1 :(得分:3)
非常感谢你的帮助,但这并不是我想要的。我做了一些改动,所以我可以从节点中获得颜色图例的不同名称'名。
以下是最终代码:
import networkx as nx
import matplotlib.pyplot as plt
import numpy as np
# For color mapping
import matplotlib.colors as colors
import matplotlib.cm as cmx
G=nx.Graph()
G.add_node("kind1")
G.add_node("kind2")
G.add_node("kind3")
G.add_node("kind4")
G.add_node("kind5")
G.add_node("kind6")
# You were missing the position.
pos=nx.spring_layout(G)
val_map = {'kind1': 2,'kind2': 2,'kind3': 2,'kind4': 1,'kind5':4,'kind6': 3}
#I had this list for the name corresponding t the color but different from the node name
ColorLegend = {'Obsolete': 2,'Initialisation': 1,'Draft': 4,'Release': 3}
values = [val_map.get(node, 0) for node in G.nodes()]
# Color mapping
jet = cm = plt.get_cmap('jet')
cNorm = colors.Normalize(vmin=0, vmax=max(values))
scalarMap = cmx.ScalarMappable(norm=cNorm, cmap=jet)
# Using a figure to use it as a parameter when calling nx.draw_networkx
f = plt.figure(1)
ax = f.add_subplot(1,1,1)
for label in ColorLegend:
ax.plot([0],[0],color=scalarMap.to_rgba(ColorLegend[label]),label=label)
# Just fixed the color map
nx.draw_networkx(G,pos, cmap = jet, vmin=0, vmax= max(values),node_color=values,with_labels=True,ax=ax)
# Setting it to how it was looking before.
plt.axis('off')
f.set_facecolor('w')
plt.legend()
f.tight_layout()
plt.show()