getTree方法必须回答一个Node对象,该对象的TAL = 2,而LEFT指向一个节点,其TAL = 1,RIGHT指向一个节点,其TAL = 3
public class Test
{
public Node getTree()
{
Node right = new Node();
Node left = new Node();
Node ny = new Node();
ny.TAL = 2;
Node ny2 = new Node();
ny2.TAL = 1;
Node ny3 = new Node();
ny3.TAL = 3;
left.LEFT = ny2;
right.RIGHT = ny3;
}
public class Node
{
public int TAL;
public Node LEFT;
public Node RIGHT;
}
}
答案 0 :(得分:1)
public class Test
{
public Node getTree()
{
Node output = new Node(); // create tree root
// create child nodes
output.LEFT = new Node();
output.RIGHT = new Node();
//set TAL values
output.TAL = 2;
output.LEFT.TAL = 1;
output.RIGHT.TAL = 3;
//return tree
return output;
}
public class Node
{
public int TAL;
public Node LEFT;
public Node RIGHT;
}
}
您还可以使用构造函数来设置TAL属性:
public class Test
{
public Node getTree()
{
//creates root node with TAL=2 using Node(int) constructor
Node output = new Node(2);
//creates left and right child nodes
output.LEFT = new Node(1);
output.RIGHT = new Node(3);
return output;
}
public class Node
{
public int TAL;
public Node LEFT;
public Node RIGHT;
//Node constructor that set TAL field
public Node(int tal)
{
TAL = tal;
}
}
}
答案 1 :(得分:0)
当您只需要三个时,您正在创建五个Node对象。 试试这个:
public class Test
{
public Node getTree()
{
// Create the nodes
Node parent = new Node();
Node right = new Node();
Node left = new Node();
// Link them
parent.LEFT = left;
parent.RIGHT = right;
// Populate their values
parent.TAL = 2;
right.TAL = 3;
left.TAL = 1;
// Return the tree
return parent;
}
public class Node
{
public int TAL;
public Node LEFT;
public Node RIGHT;
}
}