Question

我在WordPress数据库中编写了一个MySQL触发器＆amp;它给出了一个错误。我的触发器代码如下：

CREATE 
  [DEFINER = { user | CURRENT_USER }]
  TRIGGER up_trig AFTER INSERT ON `wp_postmeta` 
  FOR EACH ROW
  BEGIN
    DECLARE `pan_id` INT
    "SELECT DISTINCT (`meta_value`) INTO `pan_id`
     FROM `wp_postmeta`
     WHERE `meta_key` = 'panchayat_id' 
     AND `meta_value` = NEW.(SELECT DISTINCT meta_value 
                             FROM wp_postmeta 
                             WHERE meta_key = panchayat_id)"

    IF `pan_id` != 'NULL'  THEN
       UPDATE `wp_panchayatpost`
       SET post_count = post_count+1
       WHERE 'panchayat_id' = 'pan_id';
    END IF;
END;

它提供了以下错误消息：

错误

SQL查询：文档

CREATE [DEFINER = {user | CURRENT_USER}] TRIGGER up_trig插入后   ON wp_postmeta FOR EACH ROW BEGIN DECLARE pan_id INT＆＃34; SELECT   DISTINCT（meta_value）INTO pan_id FROM wp_postmeta WHERE   meta_key =＆＃39; panchayat_id＆＃39; AND meta_value = NEW。（选择DISTINCT   meta_value FROM wp_postmeta WHERE meta_key = panchayat_id）＆＃34;如果   pan_id！=＆＃39; NULL＆＃39;那么更新wp_panchayatpost SET post_count =   post_count +1 WHERE＆＃39; panchayat_id＆＃39; =＆＃39; pan_id＆＃39;;

MySQL说：文档

＃1064 - 您的SQL语法出错;检查与MySQL服务器版本对应的手册，以获得正确的语法靠近＆＃39; [DEFINER = {user | CURRENT_USER}] TRIGGER up_trig 插入后＃39;在第2行

Answer 1

只需删除[DEFINER = { user | CURRENT_USER }]即可。当您想要定义触发器所有者用户的类型时，它是必需的。或者将其替换为DEFINER=root（或您用于连接的任何其他用户名）。

获取MySQL触发器错误

1 个答案: