Question

我正在尝试创建mysql触发器但是收到错误

错误＃1064 - 您的SQL语法出错;检查手册对应于您的MySQL服务器版本，以获得正确的语法使用附近＆＃39;＆＃39;在第14行

这是我的sql脚本

delimiter $$
CREATE TRIGGER `update_account_balance_after_transfer` AFTER INSERT ON `balance_transfer`
 FOR EACH ROW  
    BEGIN
    IF(NEW.from_account_type='CUSTOMER') THEN
        UPDATE customer c SET c.balance = c.balance-NEW.amount WHERE c.customer_id= NEW.from_account_id;
    ELSE IF(NEW.from_account_type='Vendor') THEN
        UPDATE vendor V SET v.balance = v.balance-NEW.amount WHERE v.vendor= NEW.from_account_id;
    END IF;
    IF(NEW.to_account_type='VENDOR') THEN
        UPDATE customer c SET c.balance = c.balance+NEW.amount WHERE c.customer_id= NEW.to_account_id;
    ELSE IF(NEW.to_account_type='Vendor') THEN
        UPDATE vendor V SET v.balance = v.balance+NEW.amount WHERE v.vendor= NEW.to_account_id;
    END IF;
END $$
delimiter ;

Answer 1

删除ELSE和IF之间的空格。它应该是ELSEIF，如下所示。

delimiter $$
CREATE TRIGGER `update_account_balance_after_transfer` AFTER INSERT ON `balance_transfer`
 FOR EACH ROW  
    BEGIN
    IF(NEW.from_account_type='CUSTOMER') THEN
        UPDATE customer c SET c.balance = c.balance-NEW.amount WHERE c.customer_id= NEW.from_account_id;
    ELSEIF(NEW.from_account_type='Vendor') THEN
        UPDATE vendor V SET v.balance = v.balance-NEW.amount WHERE v.vendor= NEW.from_account_id;
    END IF;
    IF(NEW.to_account_type='VENDOR') THEN
        UPDATE customer c SET c.balance = c.balance+NEW.amount WHERE c.customer_id= NEW.to_account_id;
    ELSEIF(NEW.to_account_type='Vendor') THEN
        UPDATE vendor V SET v.balance = v.balance+NEW.amount WHERE v.vendor= NEW.to_account_id;
    END IF;
END $$
delimiter ;

MySQL IF 语法

查看演示 here

创建mysql触发器时出现1064错误

1 个答案: