数组python中最小的数字

Question

尝试查找用户输入的数组中的最小数字。这就是我所拥有的：

def main():
   numbers = eval(input("Give me an array of numbers: "))
   smallest = numbers[0]
   for i in range(0,len(numbers),1):
      if (numbers[i] < smallest):
         smallest = numbers[i]
         print("The smallest number is: ", smallest)
main()

我要找的结果是：

Give me an array of numbers: [11, 5, 3, 51]
The smallest number is 3

相反，这就是我所得到的：

Give me an array of numbers: [11, 5, 3, 51]
The smallest number is:  5
The smallest number is:  3

任何人都可以帮我弄明白我搞砸了吗？提前谢谢。

Answer 1

您可以使用min()：

print("The smallest number is: ", min(numbers))

Answer 2

循环结束后，您只需打印输出一次。

def main():
   numbers = eval(input("Give me an array of numbers: "))
   smallest = numbers[0]
   for i in range(0,len(numbers),1):
      if (numbers[i] < smallest):
         smallest = numbers[i]
   print("The smallest number is: ", smallest)
main()

或者像基督徒建议的那样使用min()。