我正在努力实现下面所述的目标,并且有很多错误。我花了很多时间试图对规则进行排序,然后打印前十名。我知道如何打印整个列表。
使用R,探索更大数据文件中的生成规则。考虑成人数据
(在R中使用> data(Adult)
命令)。
生成关联规则,置信度阈值为0.8
apriori
的外观参数
功能。打印按电梯分类的前10条规则。到目前为止,这是我的代码:
library(arules)
library(arulesViz)
data(Adult)
head(Adult)
rules <- apriori(Adult, parameter = list(supp = 0.5, conf = 0.8))
top.support <- sort(rules, decreasing = TRUE, na.last = NA, by = "support")
top.ten.support <- sort.list(top.support, partial=10)
inspect(top.ten.support)
top.confidence <- sort(rules, decreasing = TRUE, na.last = NA, by = "confidence")
top.ten.confidence <- sort.list(top.support,partial=10)
inspect(top.ten.confidence)
rules2 <- apriori(Adult, parameter=list(supp = 0.5, conf = 0.8), appearance = income)
top.lift <- sort(rules2, decreasing = TRUE, na.last = NA, by = "lift")
top.ten.lift <- sort.list(top.lift, partial=10)
inspect(top.ten.lift)
答案 0 :(得分:4)
1)打印出按支持排序的前10条规则:
R> top.support <- sort(rules, decreasing = TRUE, na.last = NA, by = "support")
R> inspect(head(top.support, 10)) # or inspect(sort(top.support)[1:10])
lhs rhs support confidence lift
1 {} => {capital-loss=None} 0.9533 0.9533 1.0000
2 {} => {capital-gain=None} 0.9174 0.9174 1.0000
3 {} => {native-country=United-States} 0.8974 0.8974 1.0000
4 {capital-gain=None} => {capital-loss=None} 0.8707 0.9491 0.9956
5 {capital-loss=None} => {capital-gain=None} 0.8707 0.9133 0.9956
...
2)打印排名前10位的规则:
R> top.confidence <- sort(rules, decreasing = TRUE, na.last = NA, by = "confidence")
R> inspect(head(top.confidence, 10))
lhs rhs support confidence lift
1 {hours-per-week=Full-time} => {capital-loss=None} 0.5607 0.9583 1.0052
2 {workclass=Private} => {capital-loss=None} 0.6640 0.9565 1.0034
3 {workclass=Private,
native-country=United-States} => {capital-loss=None} 0.5897 0.9555 1.0023
4 {capital-gain=None,
hours-per-week=Full-time} => {capital-loss=None} 0.5192 0.9551 1.0019
5 {workclass=Private,
race=White} => {capital-loss=None} 0.5675 0.9550 1.0018
...
3)
R> rules2 <- apriori(Adult, parameter=list(supp = 0.1, conf = 0.8),
appearance = list(lhs = c("income=small", "income=large"),
default = "rhs"))
R> top.lift <- sort(rules2, decreasing = TRUE, na.last = NA, by = "lift")
R> inspect(head(subset(top.lift, lhs %pin% "income"), 10))
lhs rhs support confidence lift
1 {income=large} => {marital-status=Married-civ-spouse} 0.1370 0.8535 1.8627
2 {income=large} => {sex=Male} 0.1364 0.8496 1.2710
3 {income=large} => {race=White} 0.1457 0.9077 1.0615
4 {income=small} => {capital-gain=None} 0.4849 0.9581 1.0444
5 {income=large} => {native-country=United-States} 0.1468 0.9146 1.0191
...