Question

有没有办法修剪字符串以在特定点开始和结束？

这是一个例子：我希望字符串（文本）在第一个完整停止后立即开始，并在最后一个完整停止时结束。

_string = "money is good. love is better. be lucky to have any. can't really have both"

预期产出：

"love is better. be lucky to have any."

我的尝试：

import re
pattern = "\.(?P<_string>.*?.*?).\"
match = re.search(pattern, _string)
if match != None:
    print match.group("_string")

我的尝试开始很好，但在第二个full_stop停止了。

有关如何达到预期输出的任何想法？

Answer 1

如果字符串中至少有一个点，这将有效。

print _string[_string.index(".") + 1:_string.rindex(".") + 1]
#  love is better. be lucky to have any.

如果您不想要开头的空格，那么您可以像这样删除

print _string[_string.index(".") + 1:_string.rindex(".") + 1].lstrip()
# love is better. be lucky to have any.

Answer 2

import re
_string = "money is good. love is better. be lucky to have any. can't really have both"
str1 =_string[_string.find(".")+1:]
for i in range(len(str1)-1,0,-1):
if(str1[i]=='.'):
    a=str1[:i+1]
    break
print a
#love is better. be lucky to have any.

Answer 3

如何使用.index()和.rindex()方法进行字符串切片？

string = "money is good. love is better. be lucky to have any. can't really have both"
first_full_stop = string.index('.')
last_full_stop = string.rindex('.')
string = string[first_full_stop+1:last_full_stop+1]

或者你可以按句号分割（这个可以使用任意数量的句号）：

string = "money is good. love is better. be lucky to have any. can't really have both"
string = string.split('.')
string = string[1:-1]

Answer 4

正则表达式应该是：

 \.(.*\.)

这将捕获第一个和最后一个newline

之间除.之外的所有文字

说明：

\. matches the character . literally
1st Capturing group (.*\.)
    .* matches any character (except newline)
        Quantifier: Between zero and unlimited times, as many times as possible, giving back as needed [greedy]
    \. matches the character . literally

如果您不想要开头的空间，请使用以下空格：

\.\s(.*\.)

希望这会有所帮助。

如何修剪字符串：在第一个完全停止后立即开始，最后一个结束

4 个答案: