Question

我得到以下示例

    CString line[100];

    //string line;
    ifstream myfile (_T("example.txt"));
    if (myfile.is_open())
    {
       while ( getline (myfile,line) )
       {
          cout << line << '\n';
       }
       myfile.close();
     }

该“行”如何将值存储为CString或TCHAR类型。我收到这样的错误：

错误C2664：'__ thistall std :: basic_ifstream＆gt; :: std :: basic_ifstream＆gt;（const char *，int）'

请帮帮我:)。

Answer 1

首先，这句话：

CString line[100];

定义了100个CString的数组：你确定要这个吗？

或许你只想要一个 CString来读取每一行？

// One line
CString line;

您拥有的选项是将行读为std::string，然后将结果转换为CString：

string line;
ifstream myfile ("example.txt");
if (myfile.is_open())
{
   while (getline(myfile, line))
   {
      // Convert from std::string to CString.
      //
      // Note that there is no CString constructor overload that takes
      // a std::string directly; however, there are CString constructor
      // overloads that take raw C-string pointers (e.g. const char*).
      // So, it's possible to do the conversion requesting a raw const char*
      // C-style string pointer from std::string, calling its c_str() method.
      // 
      CString str(line.c_str());

      cout << str.GetString() << '\n';
   }
   myfile.close();
}

Answer 2

std::getline()的第二个参数需要std::string，因此请先使用std::string，然后将其转换为CString

string str_line;
ifstream myfile (_T("example.txt"));
if (myfile.is_open())
{
   while ( getline (myfile, str_line) )
   {
      CString line(str_line.c_str());
      cout << line << '\n';
   }
   myfile.close();
 }

C ++逐行读取文件，但行类型为CString或TCHAR

2 个答案: