C#中PictureBox之间的碰撞检测

时间:2014-04-07 10:21:34

标签: c# picturebox collision

我的表格上有2个图片盒,一个是移动的,其方向由键控制,另一个是稳​​定的,如何检测它们之间的碰撞.....这里是我尝试过的;但失败了......

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace WindowsFormsApplication1
{
    public partial class Form1 : Form
    {

        private enum disha { up, down, left, right };
        private disha ekdisha = disha.down;


        public Form1()
        {
            InitializeComponent();
        }

        private void Form1_KeyDown(object sender, KeyEventArgs e)
        {
            if (e.KeyCode == Keys.Up)
            {
                ekdisha = disha.up;
            }
            else if (e.KeyCode == Keys.Down)
            {
                ekdisha = disha.down;
            }
            else if (e.KeyCode == Keys.Left)
            {
                ekdisha = disha.left;
            }
            else if (e.KeyCode == Keys.Right)
            {
                ekdisha = disha.right;
            }
        }

        private void timer1_Tick(object sender, EventArgs e)
        {
            if (pictureBox1.Top <= 0)
            {
                pictureBox1.Top = 0;
            }


            if (ekdisha == disha.up)
            {
                pictureBox1.Top -= 3;
            }

            else if (ekdisha == disha.down)
            {
                pictureBox1.Top += 3;
            }

            else if (ekdisha == disha.left)
            {
                pictureBox1.Left -= 3;
            }

            else if (ekdisha == disha.right)
            {
                pictureBox1.Left += 3;
            }
        }

        private void Form1_Load(object sender, EventArgs e)
        {
            if (pictureBox2.Bounds.IntersectsWith(pictureBox1.Bounds))
            {
                MessageBox.Show("Something is collided");
            }
        }
    }

}

1 个答案:

答案 0 :(得分:1)

您需要在单独的函数中编写用于检查边界的代码(您现在在Form1_Load中编写)并从timer1_Tick中调用它