Question

好的，所以我对c ++很新，这是我第一次尝试使用矢量。我的目标是将对象存储到矢量中。我试图按照这个youtube教程进行操作：

http://www.youtube.com/watch?v=iPlW5tSUOUM

我觉得除了跑步之外，我的情况几乎相同。

我只是不断收到错误，但它不会运行。任何帮助，将不胜感激：）也许它有点小，但我现在已经检查了一段时间，我看不到任何东西。

错误： 1＆gt; c：\ users \ user \ desktop \ vector objects c ++ \ testvectorobjects \ testvectorobjects \ main.cpp（61）：error C3867：＆＃39; Employees :: getSalary＆＃39;：函数调用缺少参数列表;使用＆＃39;＆amp; Employees :: getSalary＆＃39;创建指向成员的指针

1＆gt; c：\ users \ user \ desktop \ vector objects c ++ \ testvectorobjects \ testvectorobjects \ main.cpp（61）：error C2679：binary＆＃39;＆lt;＆lt;＆lt;＆＃39; ：找不到哪个运算符采用类型＆＃39;重载函数＆＃39;的右手操作数。（或者没有可接受的转换）

1＆gt; c：\ program files（x86）\ microsoft visual studio 11.0 \ vc \ include \ ostream（695）：可能是＆＃39; std :: basic_ostream＆lt; _Elem，_Traits＆gt; ＆amp; std :: operator＆lt;＆lt;＆gt;（std :: basic_ostream＆lt; _Elem，_Traits＆gt;＆amp;，const char *）＆＃39;

我有3个文件：main.cpp，Employee.h，Employees.cpp

// main.cpp中

#include <iostream>
#include <string>
#include <vector>
#include "Employee.h"

void fillVector(vector<Employees>&);
//fill vector - fills in Employee Info
//vector<Employees>& - Employees at the station
void printVector(const vector<Employees>&);
//print vector - prints the employee info
//const vector<Employees>& - employees at the station

using namespace std;

    vector<Employees> Staff;


int main(){

    fillVector(Staff);
    printVector(Staff);

}


//filling the employee vector
void fillVector(vector<Employees> & newStaff){

    int id;
    double salary;
    string name;

    cout << "Number of Employees" << endl;
    int amountEmployees;
    cin >> amountEmployees;

    for (int i = 0; i < amountEmployees; i++) {
        cout << "Enter Employee Id: ";
        cin >> id;
        cout << "Enter Employee Salary: ";
        cin >> salary;
        cout << "Enter Employee Name: ";
        cin >> name;

        Employees newEmployees(id, salary, name);
        newStaff.push_back(newEmployees);
        cout << endl;
    }
    cout << endl;

}

//printing the employee vector
void printVector(const vector<Employees>& newStaff){

    unsigned int size = newStaff.size();

    for (unsigned int i = 0; i < size; i++) {
        cout << "Employee Id: " << newStaff[i].getID << endl;
        cout << "Employee Name: " << newStaff[i].getName << end;
        cout << "Employee Salary: " << newStaff[i].getSalary << end;
        cout << endl;
    }

}

// Employee.h

//Header

#ifndef EMPLOYEE_H
#define EMPLOYEE_H

#include <iostream>
#include <string>
using namespace std;

class Employees{

    public:
        //after
        //Default Constructor
        Employees();

        //Overload constructor
        Employees(int, double, string);

        //Destructor
        ~Employees();

        //Accessor Functions
        int getID() const;
        //getId
        //return int - Id for Employee
        double getSalary() const;
        //getSalary
        //return salary - salary of Employee
        string getName() const;
        //getName 
        //return name - Name of Employee

        //Mutators
        void setId(int);
        //setId - for Employee

        void setSalary(double);
        //setSalary - for Employee

        void setName(string);
        //setName - for Employee
        //

        //before
        //ID
        //void setEmployeeId(int a){
        //employeeId = a;
        //} 
        ////Salary
        //void setSalary(double b){
        //salary = b;
        //}
        ////Name
        //void setName(string c){
        //name = c;
        //}
    private:
        //after
        //before
        int employeeId; //id
        double employeeSalary; //salary
        string employeeName; //name
};


#endif

// Employees.cpp

#include "Employee.h"


Employees::Employees() {
    employeeName = ' ';
}

Employees::Employees(int id, double salary, string name){
    employeeId = id;
    employeeSalary = salary;
    employeeName = name;
}

Employees::~Employees(){

}

int Employees::getID()const{
    return employeeId;
}

double Employees::getSalary()const{
    return employeeSalary;
}

string Employees::getName()const{
    return employeeName;
}

void Employees::setId(int id){
    employeeId = id;
}

void Employees::setSalary(double salary){
    employeeSalary = salary;
}

void Employees::setName(string name){
    employeeName = name;
}

Answer 1

 'Employees::getSalary': function call missing argument list;

这似乎很清楚：getSalary是一个函数，当你调用一个函数时需要一个参数列表：

cout << "Employee Salary: " << newStaff[i].getSalary() << endl;
                                                    ^^       ^

，同样适用于对getID和getName的调用。

修复那个也应该修复第二个错误;或者可能是endl。

的错误造成的

Answer 2

一旦你了解了一些C ++术语，我认为错误是非常自我解释的。第二部分（use '&Employees::getSalary' to create a pointer to member）实际上会让你感到困惑，因为编译器在讨论一个完全不相关的C ++功能，它认为你可能会尝试使用它。

让我们看看：

'Employees :: getSalary'：函数调用缺少参数列表

要调用一个函数，你必须用括号指定参数列表，即使你根本没有参数！

cout << "Employee Salary: " << newStaff[i].getSalary() << end;

也就是说，在这里和那里添加一些()。

Answer 3

您必须使用函数调用operator ()（应用程序运算符）来调用函数

function_name()  // call a function named function_name

因此：

cout << "Employee Id: " << newStaff[i].getID() << endl;
                                            ^^
cout << "Employee Name: " << newStaff[i].getName() << end;
                                                ^^
cout << "Employee Salary: " << newStaff[i].getSalary() << end;
                                                    ^^

Answer 4

此：

newStaff[i].getName

需要这样：

newStaff[i].getName()

等等。

向量问题，C ++不确定我做错了什么

4 个答案: