Question

我想知道，如何测试从条件语句中的列表中随机抽取的函数？这是一些示例代码。只需忽略代码应该打印的内容。

import random, time
def biomeLand():
    print "Biome: Land"

def biomeOcean():
    print "Biome: Ocean"

def biomeDesert():
    print "Biome: Desert"

def biomeForest():
    print "Biome: Forest"

def biomeRiver():
    print "Biome: River"

biomes = [biomeLand, biomeOcean, biomeDesert, biomeForest,
          biomeRiver]

def run():
    while True:
        selected_biome = random.choice(biomes)()
        time.sleep(0.5)
run()

如果从列表中调用某个函数，我怎样才能使条件语句中的程序测试？

Answer 1

也许：

def run():
    while True:
        selected_biome = random.choice(biomes)
        selected_biome()
        if selected_biome == biomeLand:
            print "biomeLand Selected"
        time.sleep(0.5)
run()

Answer 2

您可以像任何其他变量一样匹配它们：

def foo():
    print "foo"

def bar():
    print "bar"

first = foo

print (first == bar) # prints "False"
print (first == foo) # prints "True"

因此，在您的示例中，您可以使用以下内容：

if selected_biome == biomeLand:
    # do something

测试从python中的列表调用的函数

2 个答案: