我的活动不是从网络服务打印结果,而是编写" TextView"

时间:2014-04-04 07:28:35

标签: android web-services ksoap2 soap-client android-ksoap2

我希望我的练习应用程序使用来自w3schools的soap web服务并将celcius温度转换为华氏温度,并在textview中显示转换后的温度。但它只是写作" TextView "屏幕上。 LogCat只是说,

  

"未检测到GPU的仿真器。"

我该怎么办?

 package com.falafel.MyTest;
//ANDROID CLIENT OF SOAP WEB SERVICES. SAMPLE (YOUTUBE) CLIENT.
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;

import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.widget.TextView;


public class FirstScreen extends Activity {

    private static final String SOAP_ACTION= "http://www.w3schools.com/webservices/CelsiusToFahrenheit"; //soapAction will point to where the namespace is, slash, the name of the method
    private static final String NAMESPACE = "http://www.w3schools.com/webservices/";
    private static final String METHOD_NAME= "CelsiusToFahrenheit";
    private static final String URL= "http://www.w3schools.com/webservices/tempconvert.asmx";//This URL is very important. Make sure it is pointing to asmx, and not to wsdl, that is a complete URL to where the web service itself is; This is not a WSDL file.

    TextView tv;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        tv = (TextView) findViewById(R.id.textView1);
        String[] params= {SOAP_ACTION, NAMESPACE, METHOD_NAME, URL};
        new MyTask().execute(params);
    }

        private class MyTask extends AsyncTask<String, Void, SoapPrimitive>{

            @Override
            protected SoapPrimitive doInBackground(String... params) {
                //Soap Portion of this client program starts here. This is 1/3rd of the major functionality of this program, since there are three major portions.
                SoapObject Request = new SoapObject(params[1], params[2]);//If we CelsiusToFahrenheit dint take any parameters, I would be done with my soap request by this line. But it does take a string parameter (as we say in the wsdl), so we need to package the required parameters into the Request. That is, next line!
                Request.addAttribute("Celsius", "32"); //Celcius is the name of the parameter required by the function. 32 --> we are giving a hardcoded value here for simplicity. | We have to add this line for each required parameter.


                //Here starts the 2nd out of 3 major portions of this program. This portion is the SoapSerializationEnvelope, which is an important piece of what needs to happen in ksoap to call web services inside of android.
                SoapSerializationEnvelope soapEnvelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); //An important thing in creating this object is specifying which version of the soap specification we want to use. This is version 1.1
                                                                                                    //soapEnvelope is an in and out object, which means that it has 2 types of information clusters, named bodyIn which contains information we send to web service while making the call (i.e. the xml going out), and named bodyOut which brings back, from the web service, the response of the call to the web service (that is the xml coming in).
                soapEnvelope.dotNet= true; //Remember the asmx in the URL, that is this service is based in ASP.Net, and not PHP or something, so you have to specify that. If you forget to specify that, you'll get some errors complaining that some of your objects are NULL. And the tricky part is that sometimes it will work, so yeah! If you are sure that yours is a dotNet based web service, always be safe by setting it to true, and if it is not dotNet based, you'll have to set it to nottrue
                soapEnvelope.setOutputSoapObject(Request); //Pass the packaged Request to SoapEnvelope itself. SetOutputSoapObject() assigns the object to the envelope as the outbound message for the soap call.


                //3rd of the 3 major parts of this program:- Transport (HTTP transport itself)
                HttpTransportSE hts= new HttpTransportSE(params[3]);
                SoapPrimitive resultString=new SoapPrimitive("sorry","sorry","sorry");
                try{   //try-catch block to actually make the call
                    hts.call(params[0], soapEnvelope); //SOAP_ACTION contains where the web service is, appended with the function to be invoked. While all the information which needs to be sent to the web service is present (like Request) in the bodyIn portion of the soapEnvelope. After the call is successful (i.e. after the execution of this line, the bodyOut portion of this envelope will contain the response of the webservice.
                    resultString = (SoapPrimitive) soapEnvelope.getResponse();
                    //tv.setText("Status : " + resultString);
                }   
                catch (Exception e){
                    e.printStackTrace();
                }
                return resultString;
            }

            @Override 
            protected void onPostExecute(SoapPrimitive resultString){
                tv.setText("Status: " + resultString.toString());
            }
    }
}

编辑: -

我在实现前两个答案后编辑了上面的代码。但结果是&#34; 状态:错误&#34;这是第一次,然后又是&#34; TextView &#34;屏幕上。

另外更令人困惑的是,以下是LogCat的全部内容,尽管我在两个不同的模拟器上进行了测试:

04-04 04:08:56.355: D/gralloc_goldfish(1115): Emulator without GPU emulation detected.
04-04 04:08:57.705: D/dalvikvm(1115): GC_FOR_ALLOC freed 86K, 5% free 3088K/3244K, paused 65ms, total 73ms
04-04 04:08:59.905: D/dalvikvm(1115): GC_FOR_ALLOC freed 405K, 14% free 3185K/3664K, paused 52ms, total 52ms

编辑: -

再次打印&#34; 状态:错误&#34;。这是我认为异常抓住了。但为什么这种不可预测的行为?

2 个答案:

答案 0 :(得分:2)

您已声明MyTask但是您正在执行它吗?我想你错过了像

这样的东西
new MyTask().execute(params); 

onCreate

对于没有检测到GPU的&#34;模拟器。&#34;,这与您面临的问题没有任何关联。

除此之外,您的代码还包含其他一些问题。例如,在onPostExecute中,您可能需要致电.toString()resultString

答案 1 :(得分:1)

如果你正在做fremmedehenvendelser指出的事情,那么下列情况之一可能就是这样:

1.在将resultString分配给textview之前,不应将其串行化为字符串 2.如果resultString得到了正确的值,那么你的textview可能不在UI线程上,你应该尝试使用runonUithread或者将textView的引用传递给这个asyncTask,然后更新引用。