使用批处理脚本编辑XML文件

时间:2014-04-02 16:52:24

标签: xml batch-file replace xml-parsing user-input

我希望编辑位于C:\CONFIG\TEST_CONFIG.XML的XML文件,并替换其中的2个不同的值。我希望用这个文件替换以下标准:

<test.tbl>
CONFIG!CONFIG2 |1 T |125 **TN###** |151 **TN###**
</TEST.tbl>

"|125 TN###" must equal %USERINPUT1%

"|151 TN###" must equal %USERINPUT2%

我发现其他帖子已接近但难以绕过。

另一个问题是我需要保留所有间距和特殊字符。

1 个答案:

答案 0 :(得分:1)

@echo off
setlocal DisableDelayedExpansion

set USERINPUT1=First Value
set USERINPUT2=Second Field

for /F "delims=:" %%a in ('findstr /N /C:"CONFIG!CONFIG2 |1 T |125 **TN###** |151 **TN###**" C:\CONFIG\TEST_CONFIG.XML') do set num=%%a
(for /F "tokens=1* delims=:" %%a in ('findstr /N "^" C:\CONFIG\TEST_CONFIG.XML') do (
   set "line=%%b"
   setlocal EnableDelayedExpansion
   if "%%a" equ "%num%" (
      set "line=!line:|125 **TN###**=%USERINPUT1%!"
      set "line=!line:|151 **TN###**=%USERINPUT2%!"
   )
   echo(!line!
   endlocal
)) > temp.xml
move /Y temp.xml C:\CONFIG\TEST_CONFIG.XML

编辑已添加示例

input.xml中:

<test.tbl>
<p>Support the free distribution of this forecast by visiting our sponsors website.<p><b>Select forecast - </b>
<a href="?fdate=140403">Tomorrow</a> / <a href="?fdate=140404">Friday</a> / <a href="?fdate=140405">Saturday</a><p><hr>
CONFIG!CONFIG2 |1 T |125 **TN###** |151 **TN###**
<h5>Viewing forecast for Thursday, 3rd April, 2014</h5><p>Forecast last reviewed on Wednesday, 02/04/14 at 16:17
</TEST.tbl>

的Output.xml:

<test.tbl>
<p>Support the free distribution of this forecast by visiting our sponsors website.<p><b>Select forecast - </b>
<a href="?fdate=140403">Tomorrow</a> / <a href="?fdate=140404">Friday</a> / <a href="?fdate=140405">Saturday</a><p><hr>
CONFIG!CONFIG2 |1 T First Value Second Field
<h5>Viewing forecast for Thursday, 3rd April, 2014</h5><p>Forecast last reviewed on Wednesday, 02/04/14 at 16:17
</TEST.tbl>

请务必在替换中使用正确匹配的字符串。在你的例子中,你把:

CONFIG!CONFIG2 |1 T |125 **TN###** |151 **TN###**

在您的数据中,但是:

"|125 TN###" must equal %USERINPUT1%
"|151 TN###" must equal %USERINPUT2%

在错过了**数据中的匹配字符串中。我在替换中添加了**,否则它们会失败......