Question

游戏是，用户试图在洞中打球。

1。 touchCounter出错了，我希望用户只有2次尝试，当我在游戏中运行该代码时，用户有更多的尝试，这是什么错误？

final int MAX_TRY_COUNT = 2;
 int counter = 0;

 @Override
  public boolean onTouchEvent(MotionEvent event) {
     float currentX = event.getX();
     float currentY = event.getY();
     float deltaX, deltaY;
     float scalingFactor = 1.0f / ((box.xMax > box.yMax) ? box.yMax : box.xMax);



         switch (event.getAction()) {
         case MotionEvent.ACTION_DOWN:

              counter = 2;

    if (currentX >= previousX) {
    deltaX = currentX - previousX;
    ball.speedX += deltaX * scalingFactor;    
   } else if (previousX >= currentX) {
    deltaX = previousX - currentX;
    ball.speedX += deltaX * scalingFactor;  
   } if (currentY >= previousY) {
    deltaY = currentY - previousY;
    ball.speedX += deltaY * scalingFactor;    
   } else if (previousY >= currentY) {
    deltaY = previousY - currentY;
     ball.speedY += deltaY * scalingFactor;
    }




              break;              
         case MotionEvent.ACTION_UP:

if (counter >= MAX_TRY_COUNT){
              // Alert message
                return;
             }
            counter++;

         }



     // Save current x, y
     previousX = currentX;
     previousY = currentY;
     return true;  // Event handled
  }

Answer 1

你需要两个变量来处理它。

final int MAX_TRY_COUNT = 2;
int counter = 0;

在ACTION_DOWN事件中

  If(counter >= MAX_TRY_COUNT){
  // Alert message
    return;
 }
counter++;

从ACTION_UP中删除touch_counter = 1

Touchevent运行错误

1 个答案: