Question

我想利用多线程，因此我可以在模拟中拥有更多粒子。

public List<droplet> droplets = new List<droplet>();
private void collide(int indexOfA, int indexOfB)
{
    // collision code that only changes the position of droplet A and B
}

在更新方法中;

if (droplets.Count > 1)
{
    for (int i = 0; i < droplets.Count; i++)
    {
        for (int j = i; j < droplets.Count; j++)
        {
            Thread t = new Thread(() => collideParticles(i, j));
            t.Start();
        }
    }
}

我立即超出范围，当发生异常时通常为1或2。

我做错了什么，我该如何解决这个问题？

编辑：对于那些对碰撞方法有什么好处的人，请参见下文。

if (droplets[i].collisionRectangle.Intersects(droplets[j].collisionRectangle))
            {
                if (distanceBetween(droplets[i].position, droplets[j].position) < reactDistance * reactDistance)
                {
                    Vector2 sumVector = droplets[i].velocity + droplets[j].velocity;
                    Vector2 resultVector = sumVector / 2;
                    droplets[i].velocity = resultVector;
                    droplets[j].velocity = resultVector;

                    if (droplets[i].position.X > droplets[j].position.X) //x axis
                    {
                        droplets[i].velocity.X += repelSpeed;
                        droplets[j].velocity.X -= repelSpeed;

                        droplets[i].position.X -= -repelSpeed;
                        droplets[j].position.X += -repelSpeed;
                    }
                    else
                    {
                        droplets[i].velocity.X -= repelSpeed;
                        droplets[j].velocity.X += repelSpeed;

                        droplets[i].position.X += -repelSpeed;
                        droplets[j].position.X -= -repelSpeed;
                    }

                    if (droplets[i].position.Y > droplets[j].position.Y) //y axis
                    {
                        droplets[i].velocity.Y += repelSpeed;
                        droplets[j].velocity.Y -= repelSpeed;

                        droplets[i].position.Y -= -repelSpeed;
                        droplets[j].position.Y += -repelSpeed;
                    }
                    else
                    {
                        droplets[i].velocity.Y -= repelSpeed;
                        droplets[j].velocity.Y += repelSpeed;

                        droplets[i].position.Y += -repelSpeed;
                        droplets[j].position.Y -= -repelSpeed;
                    }
                }
            }

是的，这很乱。

Answer 1

我可以建议你使用线程池来做这种事情吗？分配一个线程并不便宜，你在渲染时可能会在内环中进行（哎哟！）。

我在这里看到的真正问题是，这里有记忆障碍，这意味着i＆amp;的值。 j用于所有意图和目的是非确定性的。将collideParticles更改为打印功能：

    static void collideParticles(int i, int j)
    {
        Console.WriteLine("i = {0}, j = {1}", i, j);
    }

我得到以下的喷射：

i = 1, j = 3
i = 2, j = 3
i = 3, j = 3
i = 2, j = 3
i = 2, j = 3
i = 2, j = 3

将线程生成移动到collideParticles中会产生“预期”结果。

i = 0, j = 0
i = 0, j = 1
i = 0, j = 2
i = 1, j = 1
i = 1, j = 2
i = 2, j = 2

XNA C＃多线程导致ArgumentOutOfRangeException

1 个答案: