我在使用thread_local时遇到了一些奇怪的行为,并且不确定我是做错了什么还是GCC错误。 我有以下最小的repro场景:
#include <iostream>
using namespace std;
struct bar {
struct foo {
foo () {
cerr << "foo" << endl;
}
int i = 42;
};
static thread_local foo FOO;
};
static thread_local bar::foo FREE_FOO;
thread_local bar::foo bar::FOO;
int main() {
bar b;
cerr << "main" << endl;
// cerr << FREE_FOO.i << endl;
cerr << b.FOO.i << endl;
return 0;
}
使用上面的注释行,输出如下所示:
main
0
如果没有注释,它就变成了这个:
main
foo
foo
42
42
我只是在这里错过了一些愚蠢的东西吗?
$ gcc -v
Using built-in specs.
COLLECT_GCC=gcc
COLLECT_LTO_WRAPPER=/usr/lib/gcc/x86_64-linux-gnu/4.8/lto-wrapper
Target: x86_64-linux-gnu
Configured with: ../src/configure -v --with-pkgversion='Ubuntu/Linaro 4.8.1-10ubuntu9' --with-bugurl=file:///usr/share/doc/gcc-4.8/README.Bugs --enable-languages=c,c++,java,go,d,fortran,objc,obj-c++ --prefix=/usr --program-suffix=-4.8 --enable-shared --enable-linker-build-id --libexecdir=/usr/lib --without-included-gettext --enable-threads=posix --with-gxx-include-dir=/usr/include/c++/4.8 --libdir=/usr/lib --enable-nls --with-sysroot=/ --enable-clocale=gnu --enable-libstdcxx-debug --enable-libstdcxx-time=yes --enable-gnu-unique-object --enable-plugin --with-system-zlib --disable-browser-plugin --enable-java-awt=gtk --enable-gtk-cairo --with-java-home=/usr/lib/jvm/java-1.5.0-gcj-4.8-amd64/jre --enable-java-home --with-jvm-root-dir=/usr/lib/jvm/java-1.5.0-gcj-4.8-amd64 --with-jvm-jar-dir=/usr/lib/jvm-exports/java-1.5.0-gcj-4.8-amd64 --with-arch-directory=amd64 --with-ecj-jar=/usr/share/java/eclipse-ecj.jar --enable-objc-gc --enable-multiarch --disable-werror --with-arch-32=i686 --with-abi=m64 --with-multilib-list=m32,m64,mx32 --with-tune=generic --enable-checking=release --build=x86_64-linux-gnu --host=x86_64-linux-gnu --target=x86_64-linux-gnu
Thread model: posix
gcc version 4.8.1 (Ubuntu/Linaro 4.8.1-10ubuntu9)
更新
这也提供了意想不到的结果:
#include <iostream>
using namespace std;
template<class T>
struct bar {
struct foo {
foo () {
cerr << "bar::foo" << endl;
}
int i = 42;
};
void baz() {
cerr << bar::FOO.i << endl;
}
static thread_local foo FOO;
};
struct far {
struct foo {
foo () {
cerr << "far::foo" << endl;
}
int i = 42;
};
void baz() {
cerr << far::FOO.i << endl;
}
static thread_local foo FOO;
};
template<class T> thread_local typename bar<T>::foo bar<T>::FOO;
thread_local typename far::foo far::FOO;
int main() {
cerr << "main" << endl;
bar<int> b;
b.baz();
far f;
f.baz();
return 0;
}
结果:
main
0
far::foo
bar::foo
42
答案 0 :(得分:5)
这对评论来说太长了,但我并没有声称完全理解它。
我有一个较短的版本,您可以在Coliru
中运行#include <iostream>
using namespace std;
struct foo {
int i;
foo() : i{42} {}
};
struct bar {
static thread_local foo FOO;
};
thread_local foo bar::FOO;
int main() {
//cerr << string((bar::FOO.i == 42) ? "Ok" : "Bug") << endl; //Ok
cerr << string((bar().FOO.i == 42) ? "Ok" : "Bug") << endl; //Bug
}
我认为这个bug存在于这个gcc源文件中
https://chromium.googlesource.com/native_client/nacl-gcc/+/upstream/master/gcc/cp/decl2.c
此时gcc正在尝试确定FOO
是bar
的静态成员,是否需要包装函数来检测它是否已被初始化...它决定是否需要包装器,这是不正确的。它会检查
缺陷是:
由于初始化是由构造函数完成的,我认为这是混淆的来源,调用构造函数,但值是常量。
这是代码
/* Returns true iff we can tell that VAR does not have a dynamic
initializer. */
static bool
var_defined_without_dynamic_init (tree var)
{
/* If it's defined in another TU, we can't tell. */
if (DECL_EXTERNAL (var))
return false;
/* If it has a non-trivial destructor, registering the destructor
counts as dynamic initialization. */
if (TYPE_HAS_NONTRIVIAL_DESTRUCTOR (TREE_TYPE (var)))
return false;
/* If it's in this TU, its initializer has been processed. */
gcc_assert (DECL_INITIALIZED_P (var));
/* If it has no initializer or a constant one, it's not dynamic. */
return (!DECL_NONTRIVIALLY_INITIALIZED_P (var)
|| DECL_INITIALIZED_BY_CONSTANT_EXPRESSION_P (var));
}
/* Returns true iff VAR is a variable that needs uses to be
wrapped for possible dynamic initialization. */
static bool
var_needs_tls_wrapper (tree var)
{
return (!error_operand_p (var)
&& DECL_THREAD_LOCAL_P (var)
&& !DECL_GNU_TLS_P (var)
&& !DECL_FUNCTION_SCOPE_P (var)
&& !var_defined_without_dynamic_init (var));
}