Question

我已经在这几个星期了我想绘制1个列表，然后在同一个窗口中快速删除该列表并绘制另一个列表。

原因是我有一个实时进入的EEG信号，我将每40个样本转换为频域然后绘制它们以试图检测不同的认知状态。

现在我刚从脑袋里创建了两个列表，我希望列表1出现，然后列出两个列表，很快就会出现在它的位置

我已经尝试了matplotlib动画，但我还没弄明白如何使用它对我来说很复杂。

from numpy import sin, linspace, pi
from pylab import plot, show, title, xlabel, ylabel, subplot
from scipy import fft, arange
import time

lst1 = [1000,1100,1000,1150,1100,1090,1300,1700,2000,1500,1200,1100,1000,1100,1100,1000,1150,1100]

lst = [1000,1060,1200,1600,2000,1400,1030,1300,1600,2000,1400,1100,1000,1400,1700,1800,1500,1100]


def plotSpectrum(y,Fs):
 """
 Plots a Single-Sided Amplitude Spectrum of y(t)
 """

 n = len(lst) # length of the signal
 k = arange(n)
 T = n/Fs
 frq = k/T # two sides frequency range
 frq = frq[range(n/2)] # one side frequency range

 Y = fft(lst)/n # fft computing and normalization
 Y = Y[range(n/2)]

 plot(frq,abs(Y),'r') # plotting the spectrum
 xlabel('Freq (Hz)')
 ylabel('|Y(freq)|')


Fs = 18.0;  # sampling rate
Ts = 1.0/Fs; # sampling interval
t = arange(0,1,Ts) # time vector


subplot(2,1,1)
plot(t,lst)
xlabel('Time')
ylabel('Amplitude')
subplot(2,1,2)
plotSpectrum(lst,Fs)
show()

#time.sleep(5) #here is where id like the second list to appear
#plotSpectrum(lst1,Fs)
#show()

Answer 1

对于简单的动画，您可以使用pause。

from pylab import plot, show,  xlabel, ylabel, subplot, draw, pause

# Lists to plot
list1 = [1000,1100,1000,1150,1100,1090,1300,1700,2000,1500,1200,1100,1000,1100,1100,1000,1150,1100]
list2 = [1000,1060,1200,1600,2000,1400,1030,1300,1600,2000,1400,1100,1000,1400,1700,1800,1500,1100]

# Setup the axis
subplot(1,1,1)
xlabel('Time')
ylabel('Amplitude')

# Plot the first line
lines = plot(list1,'r')
show() 
pause(1) # pause

# Remove the first line
oldLine = lines.pop()
oldLine.remove()

# Plot the second line
lines = plot(list2,'g')
draw()

绘制列表，清除，然后使用python在同一窗口上绘制不同的列表

1 个答案: