Question

这是我必须创建的程序指令：该计划是一名警察必须输入一个速度区＆＃39;他们做的每一个班次。那个速度区域在他们输入的答案中是一个整数。然后他们得到第二个问题来填写询问他们的车速是多少？＆＃39;。此输入答案也必须是整数。如果汽车行驶的速度比速度区快。他们在轮班前只进行过一次推算，然后每隔1公里就会因超过“速度区”而被罚款10美元。因此，如果汽车超过10公里，则罚款100美元。如果汽车行驶的速度低于估算的速度区域，那么没有罚单被罚款。如果任何罚单被罚款，该官员必须输入车型名称。 I.E日产，奥迪，法拉利......然后他们必须打印出来，就像警察票一样。这一切都必须在“速度区”之外重复。

这是我的代码：

fine=int(0)

un_speed_limit = 0

while not un_speed_limit:

    speed_limit=int(input("What is your speed zone? "))
    try:
        un_speed_limit = int(speed_limit)
    except ValueError:
        print("That is not a number! ")
pass_car_speed=print("\nType '000' to kill program.\n\n")

while pass_car_speed !=000:

    try:
        pass_car_speed=int(input("What speed is the car going? "))
    except ValueError:
        print("Invalid number! ")
    else:
        if pass_car_speed==000:
            break
        if pass_car_speed > speed_limit:
            fine=(pass_car_speed-speed_limit)*10
    if pass_car_speed <= speed_limit:
        print("This car is under the limit. No ticket needed! \n")
    if pass_car_speed > speed_limit:
        name=str(input("What is the car model name? "))
        print("____________________________________________\n")
        print("   | P O L I C E   T I C K E T |   \n")
        print("   | Speed: ",pass_car_speed,"   \n")
        print("   | Fine Cost: ",fine,"    \n")
        print("   | Car Name: ",name,"  ")
        print("____________________________________________\n")

代码已停止：我对此代码的唯一常见错误是需要帮助的是此消息

ValueError: invalid literal for int() with base 10: (what ever I typed)

当我没有输入一个整数来表示你的速度区是什么时，会出现这个唯一的消息？＆＃39;

Answer 1

此代码中存在许多错误。

这是更正版本，你应该花一些时间来分析这个。

while True:
    try:
        speed_limit = int(input("What is your speed zone? "))
        break
    except ValueError:
        print("That is not a number! ")
        continue

while True:
    print("What speed is the car going?")
    try:
        pass_car_speed = int(input( "Enter speed, or 0 to quit: "))
    except ValueError:
        print("Invalid number! ")
        continue

    if not pass_car_speed: # 0 is False, non-zero True
        break # quit loop (and program)

    if pass_car_speed <= speed_limit:
        print("This car is under the limit. No ticket needed!")
    else:
        fine = (pass_car_speed - speed_limit) * 10
        name = input("What is the car model name? ")
        print("____________________________________________")
        print("   | P O L I C E   T I C K E T |   ")
        print("   | Speed: ",pass_car_speed,"   ")
        print("   | Fine Cost: ",fine,"    ")
        print("   | Car Name: ",name,"  ")
        print("____________________________________________")

print("Goodbye!")

请告诉我，如果您需要就学习中应该关注的内容提出一些建议，以便将来避免使用它们。

Answer 2

您尝试将speed_limit转换为int两次。一个被Try / Except子句包围，一个不是。只需从非冗余的呼叫中移除int()呼叫，即行

speed_limit=int(input("What is your speed zone? "))

您似乎也指定了un_speed_limit但从未使用它，您应该删除它并使用speed_limit。

Answer 3

我不得不改变行

pass_car_speed=print("\nType '000' to kill program.\n\n")

到

pass_car_speed=input("\nType '000' to kill program.\n\n")

让程序工作。

Python - 初学者代码很少混淆

3 个答案: