Question

我有一个switch语句，用于检查棋子中棋子移动的有效性。如果移动看起来有效，我让流程继续，如果移动没有导致语句return false，则该函数的结束语句为return true。我有代码来处理主教和城堡移动的检查，但我正在努力找到一种干嘛的方式对女王进行两套测试：

switch (from_piece[0]) {
    case this.CASTLE:
        if (from[0] === to[0]) {
         //continue to run checks
        } else if (from[1] === to[1]) {
         //continue to run checks
        } else {
            return false;
        };
        break;
    case this.BISHOP:
        if (Math.abs(from[1] - to[1]) === Math.abs(from[0] - to[0])) {
         //continue to run checks
        } else {
            return false;
        };
        break;
    case this.QUEEN:
     // run both bishop and castle tests
}

Answer 1

这个逻辑太复杂了，只能用switch语句。您可以将测试移动到函数中并像这样调用它们：

switch (from_piece[0]) {
    case this.CASTLE:
        validRook()
        break;
    case this.BISHOP:
        validBishop();
        break;
    case this.QUEEN:
       validRook();
       validBishop();
       break;
}
function validRook(){
    if (from[0] === to[0]) {
          return true;
    } else if (from[1] === to[1]) {
          return true;
    } else {
          return false;
    }
}
function validBishop(){
    if (Math.abs(from[1] - to[1]) === Math.abs(from[0] - to[0])) {
      return true;
    } else {
      return false;
    }
}

国际象棋干运行检查

1 个答案: