Question

我的JSON字符串是：

[
    {'Local':'webaddress'},
    {'QA':'webaddress1'}
]

我的代码是：

NSMutableDictionary *dataDictonary = [NSJSONSerialization
                                       JSONObjectWithData:responseData
                                       options:0
                                       error:nil];


        NSArray *keys = [dataDictonary allKeys];
        NSArray *values = [dataDictonary allValues];
        int i=0;
        NSLog(@"",[keys count]);
        NSLog(@"",[values count]);
        int i=0;
        for ( NSString *items in keys )
        {
            NSLog(@"----");
            NSLog(@"Name: %@", items);
            NSLog(@"Address: %@", values[i++]);
            NSLog(@"----");
        }

这里我得到的大小在NSlog中没什么空白而且不能解析这个值不要不为什么。请帮忙..

Answer 1

您的JSON是一个包含对象的数组，因此您需要将其转换为NSArray：

NSString *json_string = @"[{\"Local\": \"webaddress\" }, {\"QA\": \"webaddress1\" }]";
NSError *error;
NSArray *JSON =
[NSJSONSerialization JSONObjectWithData: [json_string dataUsingEncoding:NSUTF8StringEncoding]
                                options: NSJSONReadingMutableContainers
                                  error: &error];

NSLog(@"Local: %@", JSON[0][@"Local"]); // output is: Local: webaddress

<强>更新

// itherate through array
for(NSDictionary *dictionary in JSON)
{
    //now you can iterate throug each dicitonary
    NSEnumerator *enumerator = [dictionary keyEnumerator];
    id key;

    while((key = [enumerator nextObject])){
        NSLog(@"key=%@ value=%@", key, [dictionary objectForKey:key]);
    }
}

日志如下所示：

key =本地值= webaddress

key = QA值= webaddress1

在iOS中解析Json而没有常见的密钥

1 个答案: