Question

我试图将json内容解析为我的Android应用程序。我使用firebase db来获得结果。

我有什么

private void StartParse() {
        JsonObjectRequest jsonObjReq = new JsonObjectRequest(Request.Method.GET,
                webserviceUrl, null, new Response.Listener<JSONObject>() {

        @Override
        public void onResponse(JSONObject response) {
            Log.d("Repsonse", response.toString());

            try {
                // Parsing json object response
                // response will be a json object

                String cover = response.optString("cover").toString();
                String ip_address = response.optString("ip_address").toString();
                String port = response.optString("port").toString();
                String info = response.optString("info").toString();
                String uid = response.optString("uid").toString();

                Map<String, String> map = new HashMap<String, String>();
                map.put(cover, cover.toString());
                // and so on..
            } catch (Exception e) {
                e.printStackTrace();
                Toast.makeText(getApplicationContext(),
                        "Error: " + e.getMessage(),
                        Toast.LENGTH_LONG).show();
            }
        }
    }, new Response.ErrorListener() {

        @Override
        public void onErrorResponse(VolleyError error) {
            VolleyLog.d("Response", "Error: " + error.getMessage());
            Toast.makeText(getApplicationContext(),
                    error.getMessage(), Toast.LENGTH_SHORT).show();
            // hide the progress dialog
        }
    });

    // Adding request to request queue
    AppController.getInstance().addToRequestQueue(jsonObjReq);

}

我需要什么 是我在这里有这个json的回应：

{  
"-KFOmfn3XcmM3BsrWYcZ":{  
  "company":"A17",
  "country":"France",
  "email":"test12@gmail.com",
  "uid":"720363f7-84f1-4a35-9551-9422da991835"
},
"-KTCLolTzHO0KFcuQR3B":{  
  "company":"B13",
  "country":"Sweden",
  "email":"test14@gmail.com",
  "uid":"7eade882-c182-441e-8793-94c6a1879a52"
},
"-KFcuQR3B1KTCLsa43BK10":{  
  "company":"C23",
  "country":"Denmark",
  "email":"France",
  "uid":"7eade882-c182-441e-8793-94c6a1879a52"
},
"-CLHOcuQoKFzRTl3BKx0T":{  
  "company":"4SS",
  "country":"Italy",
  "email":"test1@gmail.com",
  "uid":"7eade882-c182-441e-8793-94c6a1879a52"
}
}

响应是json文件，但我怎样才能获取值？所以我可以只有一个数值的数组。

Answer 1

    Iterator<String> iter = json.keys();
while (iter.hasNext()) {
    String key = iter.next();
    try {
        Object value = json.get(key);
    } catch (JSONException e) {
        // Something went wrong!
    }
}

Answer 2

没有Json数组，因此您可以逐个解析对象键。像这样的东西

JSONObject jsonObject = new JSONObject(response);
String company = jsonObject.getJSONObject("-KFOmfn3XcmM3BsrWYcZ").getString("company");
String country= jsonObject.getJSONObject("-KFOmfn3XcmM3BsrWYcZ").getString("country");
// email and uid same
String company1 = jsonObject.getJSONObject("-KTCLolTzHO0KFcuQR3B").getString("company");
String country1= jsonObject.getJSONObject("-KTCLolTzHO0KFcuQR3B").getString("country");

......

没有键的JsonObject解析

2 个答案: