我知道有很多关于JSON序列化的问题,但我似乎还没有理解它。
鉴于以下课程:
import json
class BaseMongoObject(object):
def __init__(self):
pass
def jsonify(self):
return json.dumps(self, default=lambda o: o.__dict)
以下派生类:
from assetfacts import AssetFacts
from bmo import BaseMongoObject
class Asset(BaseMongoObject):
def __init__(self):
BaseMongoObject.__init__(self)
self.facts = AssetFacts()
self.serial = None
尝试使用以下测试代码调用asset.jsonify()
:
from asset import Asset
def test_me():
a = Asset()
a.serial = '123asdf'
print a.jsonify()
if __name__ == '__main__':
test_me()
产生以下内容:
Traceback (most recent call last):
File "../bin/test.py", line 17, in <module>
test_me()
File "../bin/test.py", line 13, in test_me
print a.jsonify()
File "/Users/vlazarenko/MP/ac/lib/bmo.py", line 8, in jsonify
return json.dumps(self, default=lambda o: o.__dict)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/__init__.py", line 250, in dumps
sort_keys=sort_keys, **kw).encode(obj)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/encoder.py", line 207, in encode
chunks = self.iterencode(o, _one_shot=True)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/encoder.py", line 270, in iterencode
return _iterencode(o, 0)
File "/Users/vlazarenko/MP/ac/lib/bmo.py", line 8, in <lambda>
return json.dumps(self, default=lambda o: o.__dict)
AttributeError: 'Asset' object has no attribute '_BaseMongoObject__dict'
我会在哪里脑力下降这个?理想情况下,我不想被大量的继承所困扰,只是从顶部开始序列化。
答案 0 :(得分:1)
您希望jsonify self.__dict__
代替:
def jsonify(self):
return json.dumps(self, default=lambda o: o.__dict__)
在子类中只有{em>以开头并带有双下划线的名称为mangled to protect them from accidental overriding,.__dict
被重写为._BaseMongoObject__dict
。