首先,我得到了我的班级的间谍实例:
TestedClass testedClass = spy(new TestedClass(Robolectric.buildActivity(Activity.class).create().get());
然后,测试类发生了一些变化: testedClass.someString =“不管”
然后,我模拟向在测试类中注册的广播接收器发送意图:
ShadowApplication shadowApplication = Robolectric.getShadowApplication();
Intent intent = new Intent(ConnectivityManager.CONNECTIVITY_ACTION);
List<BroadcastReceiver> broadcastReceivers = shadowApplication.getReceiversForIntent(intent);
broadcastReceivers.get(0).onReceive(Robolectric.application, intent);
在列表中找到BroadcastReceiver,因此我可以调用onReceive和onReceive事件:
public void onReceive(Context context, Intent intent) {
Log.i(tag, someString);
}
但是,出现的TestedClass对象是未初始化的版本,它是:someString == ""
它与被窥探的物体不同。
也许,这是正常行为,但我希望获得我为测试创建的相同实例,而不是创建并行创建的模拟实例。
答案 0 :(得分:0)
这取决于您实例BroadcastReceiver的方式。
如果使用默认值对BroadcastReceiver进行实例化,则不会执行对BroadcastReceiver的模拟调用
//Class member myBroadcastReceiver
public BroadcastReceiver myBroadcastReceiver = new MyBroadcastReceiver();
但是,如果稍后实例化BroadcastReceiver,它可以正常工作:
public myBroadcastReceiver;
public initializeBroadcastReceiver() {
myBroadcastReceiver = new MyBroadcastReceiver();
}
这些都是事实,尽管如此,我仍然不知道第一种情况是预期行为还是Robolectric的缺陷。