Question

是否可以使用简单的代码一次性注册它们？或者他们必须逐一取消注册？

Answer 1

我知道这是一个老问题，但为什么不使用广播接收器来获取一个意图，然后触发所有接收器取消注册？（想要发布比当前答案更准确的内容）

在响应的片段/活动中，你把它放在：

public class PanicFragment extends Fragment {

  IntentFilter killFilter = new IntentFilter("your.app.name.some.awesome.action.title");

  BroadcastReceiver kill = new BroadcastReceiver() {

    @Override
    public void onReceive(Context context, Intent intent) {
      context.unregisterReceiver(receiver); // The actual receiver you want to unreigster
      context.unregisterReceiver(this); // The one you just created

    }
  };

（不要忘记在创建片段/活动时最初注册接收器）

在您的服务或其他活动中，或者您想要的任何内容：

  private void callThisToUnregisterAllYourReceivers(Context context) {
    Intent killThemAll = new Intent();
    killThemAll.setAction("your.app.name.some.awesome.action.title");
    context.sendBroadcast(killThemAll);
  }

我希望这在任何方面都有帮助

Answer 2

你必须逐一做到这一点。活动不应该有很多，如果有的话，所以我不希望这太繁琐。

Answer 3

我不会使用其他BroadcastReceiver删除其他广播接收器。

以下是我在应用程序类中添加的内容：

private static List<BroadcastReceiver> broadcastReceivers = new LinkedList<>();

public void addReceiver(BroadcastReceiver receiver, IntentFilter filter) {
    mContext.registerReceiver(receiver, filter);
    broadcastReceivers.add(receiver);
}

public void removeReceiver(BroadcastReceiver receiver) {
    unregisterReceiver(receiver);
    broadcastReceivers.remove(receiver);
}

public List<BroadcastReceiver> getAllReceivers() {
    return broadcastReceivers;
}

public void removeAllReceivers() {
    for (BroadcastReceiver receiver : getAllReceivers()) {
        removeReceiver(receiver);
    }
}

取消注册活动中注册的所有广播接收者

3 个答案: