Question

代码：

import sys
from tkinter import *

credit = 0
coins = 0
choice = 0


credit1 = 0
coins = 0
prices = [200,150,160,50,90]
item = 0
i = 0
temp=0
n=0
choice1 = 0
choice2 = 0

credit1 = 0
coins = 0
prices = [200,150,160,50,90]
item = 0
i = 0
temp=0
n=0
choice1 = 0
choice2 = 0

def insert():
    insert = Tk()

    insert.geometry("450x250")
    iLabel = Label(insert, text="Enter coins.[Press Buttons]").grid(row=1, column=1)

    tenbutton = Button(insert, text="10p").grid(row=2, column=1)
    twentybutton = Button(insert, text="20p").grid(row=3, column=1)
    fiftybutton = Button(insert, text="50p").grid(row=4, column=1)
    poundbutton = Button(insert, text="£1").grid(row=5, column=1)

我正在创建一个模拟自动售货机的程序。我怎么告诉Python检查＆＃39;如果按下了一个按钮？在伪代码中它将是：

if tenbutton is pressed:
   Add 10p to credit

我如何用Python编写＃34;如果按下了十按钮＆＃34;？提前谢谢。

Answer 1

您可以将command添加到将回调函数的Tkinter Button小部件中：

def tenbuttonCallback():
    global credit
    credit += 10

tenbutton = Button(insert, text="10p", command=tenbuttonCallback)
tenbutton.grid(row=2, column=1)

请参阅：http://effbot.org/tkinterbook/button.htm

Answer 2

很简单，定义一个按钮按下后调用的功能。像这样：

def addCredit():
    global credit
    credit+=10

然后将这个简单的功能分配给你的按钮：

tenbutton = Button(insert, text="10p", command=addCredit).grid(row=2, column=1)

顺便说一句，你的代码在某个地方要求class。使用如此多的全局变量通常是一种不好的做法。另一个挑剔是from tkinter import *，它破坏了可读性。我建议import tkinter as tk。

Answer 3

from tkinter import *
import tkinter
import tkinter.messagebox

root = Tk()


def fun(arg):
    if arg == 1:
        tkinter.messagebox.showinfo("button 1", "button 1 used")
    elif arg == 2:
        tkinter.messagebox.showinfo("button 2", "button 2 used")
    elif arg == 3:
        tkinter.messagebox.showinfo("button 3", "button 3 used")
    elif arg == 4:
        tkinter.messagebox.showinfo("button 4", "button 4 used")


b1 = Button(root, text="Quit1", command=lambda: fun(1))
b1.pack()
b2 = Button(root, text="Quit2", command=lambda: fun(2))
b2.pack()
b3 = Button(root, text="Quit3", command=lambda: fun(3))
b3.pack()
b4 = Button(root, text="Quit4", command=lambda: fun(4))
b4.pack()

root.mainloop()

检查python中是否按下了按钮？

3 个答案: