Question

我在MySQL中运行此查询：

SELECT MAX(arg1) as longest, MIN(arg1) as shortest FROM voipnow.ast_queue_log 
        WHERE queuename = '0536*401' 
        AND DATE(time) = '2014-03-17' 
        AND event = 'CONNECT' 
        ORDER BY time DESC

但它正在回归：

longest = 9
shortest = 10

我在这里做错了什么？ - 他们应该是相反的方式

Answer 1

看起来这些字段是文本，您正在查找按字母顺序排列的最大/最小值。

“9”＆gt; “10”

Answer 2

您是否尝试过ASC订购？

SELECT MAX(arg1) as longest, MIN(arg1) as shortest FROM voipnow.ast_queue_log 
    WHERE queuename = '0536*401' 
    AND DATE(time) = '2014-03-17' 
    AND event = 'CONNECT' 
    ORDER BY time ASC

Answer 3

假设：它们存储为字符串，“1 ...”＆lt;“9 ...”

尝试：

  SELECT MAX(arg1 + 0) as longest,
         MIN(arg1 + 0) as shortest
    FROM voipnow.ast_queue_log 
   WHERE queuename = '0536*401' 
     AND DATE(time) = '2014-03-17' 
     AND event = 'CONNECT' 
ORDER BY time DESC

在MySQL中选择MIN和MAX

3 个答案: