Question

我的for循环遇到了麻烦。我有一个基本的2次表，从1到10上升（见下文）。我正在尝试添加结果，以便在每次循环后，allResult显示添加的所有结果的值。它需要显示每个循环后添加的所有结果。而且我不知道如何去做。更好的描述是代码中评论的期望结果。

我的代码......

int main(){

int allResult;

for( int i = 1; i < 11; i++)
{

    int result = 2*i;

    cout << 2 << " times " << i << " = " <<  result << endl;

    // I want allResult to store results added. so after first loop, result = 2 so allResult = 2
    // after second loop, result = 4. so allResult should be 6. (results from 1 and 2 added)
    // after third loop, result = 6 so allResult should be 12. (results from 1, 2 and 3 added)
    // I'm trying to apply this to something else, that uses random numbers, so i cant just * result by 2.


}
system("pause");
}

Answer 1

int allResult = 0;
for( int i = 1; i < 11; i++)
{
     allResult += 2*i;  
    cout << 2 << " times " << i << " = " <<  2*i << endl;

}

Answer 2

int allResult = 0;
for( int i = 1; i < 11; i++)
{
    int result = 2*i;

    cout << "2 times " << i << " = " <<  result << endl;
    allResult += result;
    cout << "allResult: " << allResult << endl;
}

Answer 3

int main()
{

int allResult=0;

 for( int i = 1; i < 11; i++)
  {

      int result = 2*i;

      allResult=allResult+result; 
/*Initially allResult is 0. After each loop iteration it adds to its previous 
value. For instance in the first loop it was allResult=0+2, 
which made allResult equal to 2. In the next loop allResult=2+4=6. 
Third Loop: allResult=6+6=12. Fourth loop:allResult 12+8=20 and so on..*/

cout << 2 << " times " << i << " = " <<  result << endl;
  }

      system("pause");
}

在每次迭代后添加for循环的结果

3 个答案: