所以我正在为大学做一个电影预订项目,但我们还没有涵盖继承。 我想在main中访问我的数组,它是在一个单独的类中。我希望在满足一个案例时访问该数组。
主要
#include <iostream>
#include <string>
#include "cinema.cpp"
#include "screen.cpp"
#include "screen.cpp"
using namespace std;
void main()
{
int loop=1;
string Film;
int inputFilm;
while(loop==1)
{
cout << "Please select film \n ";
cout<<"\n\n";
cout << " 1: Godzilla [Screen 1] \n 2: Waking Life [Screen 2] \n 3: Saving Private Ryan [Screen 3] \n 4: LOTR [Screen 4] \n 5: The Departed [Screen 5] \n 6: Knocked Up [Screen 6] \n";
cout << "\n Enter a screen number";
cin >> inputFilm;
switch(inputFilm)
{
case 1:
Film = "Godzilla";
cout <<"You have chosen: "+Film;
cout << "\n";
break;
case 2:
Film = "Waking Life";
cout <<"You have chosen: "+Film;
cout << "\n";
break;
case 3:
Film = "Saving Private Ryan";
cout <<"You have chosen: "+Film;
cout << "\n";
break;
case 4:
Film = "LOTR";
cout <<"You have chosen: "+Film;
cout << "\n";
break;
case 5:
Film = "The Departed";
cout <<"You have chosen: "+Film;
cout << "\n";
break;
case 6:
Film = "Knocked Up";
cout <<"You have chosen: "+Film;
cout << "\n";
break;
}
break;
cout << "Please eneter a seat row";
}
system("pause");
}
包含数组的类
#include <iostream>
#include <string>
#include "cinema.h"
using namespace std;
cinema::cinema()
{
string ScreenArray [6];
ScreenArray [0] = "Godzilla";
ScreenArray [1] = "Waking Life";
ScreenArray [2] = "Saving Private Ryan";
ScreenArray [3] = "LOTR";
ScreenArray [4] = "The Departed";
ScreenArray [5] = "Knocked UP";
address = "Golden Island Shopping Center";
}
string cinema::getAddres()const
{
return address;
}
//int cinema::NumOfScreens()const
//{
// return NumOfScreens;
//}
答案 0 :(得分:0)
使用类可以简化操作,但是这里不需要它们(除非赋值调用它)。
Cinema
构造函数中的数组是该构造函数的本地数据。
将其移至main
。
顺便说一下,main
绝对必须具有结果类型int
。 Microsoft Visual C ++允许void
,他们的示例通常具有void
的{{1}}结果类型,但这是非标准的;只有微软能够以微妙的方式提供非标准的东西才能帮助供应商锁定。除了有效地将代码限制到特定的编译器之外,它也是绝对新手的标志,一旦用main
替换void
,你就不再这样了。 ; - )
附录:
这是一个代码示例,用于执行我认为您到目前为止要执行的操作:
int