Question

我有一个短裤数组（short []），我需要写出一个文件。最快的方法是什么？

Answer 1

使用BinaryWriter

    static void WriteShorts(short[] values, string path)
    {
        using (FileStream fs = new FileStream(path, FileMode.OpenOrCreate, FileAccess.Write))
        {
            using (BinaryWriter bw = new BinaryWriter(fs))
            {
                foreach (short value in values)
                {
                    bw.Write(value);
                }
            }
        }
    }

Answer 2

根据Jon B的回答，如果您的文件包含任何其他数据，您可能希望在数据前面加上值的数量。

即：

static void WriteShorts(short[] values, string path)
{
    using (FileStream fs = new FileStream(path, FileMode.OpenOrCreate, FileAccess.Write))
    {
        using (BinaryWriter bw = new BinaryWriter(fs))
        {
            // Write the number of items
            bw.Write(values.Length);

            foreach (short value in values)
            {
                bw.Write(value);
            }
        }
    }
}

Answer 3

BinaryFormatter 实际上，与基本类型数组（obj.GetType（）。IsPrimitive）一起使用时读取和写入的强度大约快10倍，即不适用于十进制和字符串（不是原始的），当然不适用于任何其他结构或类，而是非常慢。

[Test]
public void TestShortArray()
{
  var n = 100000000;
  var input = new short[n];
  var r = new Random();
  for (var i = 0; i < n; i++) input[i] = (short)r.Next();
  var bf = new BinaryFormatter();
  var sw = new Stopwatch();
  using (var ms = new MemoryStream())
  {
    sw.Start();
    bf.Serialize(ms, input);
    sw.Stop();
    Console.WriteLine("BinaryFormatter serialize: " +
      sw.ElapsedMilliseconds + " ms, " + ms.ToArray().Length + " bytes");
    sw.Reset();
    ms.Seek(0, SeekOrigin.Begin);
    sw.Start();
    var output = (short[])bf.Deserialize(ms);
    sw.Stop();
    Console.WriteLine("BinaryFormatter deserialize: " +
      sw.ElapsedMilliseconds + " ms, " + ms.ToArray().Length + " bytes");
    Assert.AreEqual(input, output);
  }
  sw.Reset();
  using (var ms = new MemoryStream())
  {
    var bw = new BinaryWriter(ms, Encoding.UTF8, true);
    sw.Start();
    bw.Write(input.Length);
    for (var i = 0; i < input.Length; i++) bw.Write(input[i]);
    sw.Stop();
    Console.WriteLine("BinaryWriter serialize: " +
      sw.ElapsedMilliseconds + " ms, " + ms.ToArray().Length + " bytes");
    sw.Reset();
    ms.Seek(0, SeekOrigin.Begin);
    var br = new BinaryReader(ms, Encoding.UTF8, true);
    sw.Start();
    var length = br.ReadInt32();
    var output = new short[length];
    for (var i = 0; i < length; i++) output[i] = br.ReadInt16();
    sw.Stop();
    Console.WriteLine("BinaryReader deserialize: " +
      sw.ElapsedMilliseconds + " ms, " + ms.ToArray().Length + " bytes");
    Assert.AreEqual(input, output);
  }
}

输出：

BinaryFormatter serialize: 175 ms, 200000028 bytes
BinaryFormatter deserialize: 79 ms, 200000028 bytes
BinaryWriter serialize: 1499 ms, 200000004 bytes
BinaryReader deserialize: 1599 ms, 200000004 bytes

因此，只要有原始类型的数组或数组数组但不是多维数组（！），就使用BinaryFormatter。如果你的数据类型是例如Point3（double），你应该填充double []并将其序列化。仅对复杂/混合类型，字符串，小数和奇异值使用BinaryWriter。

当处理byte []时，BinaryFormatter和BinaryWriter同样具有高性能（并且速度非常快）。如果您能够以有效的方式将类型转换为字节数组，则可以通过这种方式获得更快的性能。

在C＃中将short []数组写入文件的最佳方法是什么？

3 个答案: